Answer:
760 mm of Hg
Explanation:
If the gases A , B and C are non reacting , then according to <u>Dalton's </u><u>Law </u><u>of</u><u> </u><u>Partial </u><u>Pressure</u> the total pressure exerted is equal to sum of individual partial pressure of the gases .
If there are n , number of gases then ,
Here ,
- Partial pressure of Gas A = 400mm of Hg
- Partial pressure of Gas B = 220 mm of Hg
- Partial pressure of Gas C = 140mm of Hg
Hence the total pressure exerted is ,
Substitute ,

Add ,

<u>Hence</u><u> the</u><u> </u><u>total</u><u> pressure</u><u> exerted</u><u> by</u><u> the</u><u> </u><u>gases </u><u>is </u><u>7</u><u>6</u><u>0</u><u> </u><u>mm </u><u>of </u><u>Hg</u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
Answer:-
95 grams
Explanation:-
Let the mass of water to be added be M
So total mass = 5 + M
So 5% of this solution has 5g of NaCl by mass.
∴ (M+5) x (5/100) = 5
M+5 = 5 x 100/5
M+5=100
M= 100-5
95
So amount of water to be added is 95 gram
Answer: 0.025 moles of nitrogen gas are there in the sample.
Explanation:
According to ideal gas equation:
P = pressure of gas = 1.03 atm
V = Volume of gas = 568 ml = 0.568 L (1L=1000ml)
n = number of moles = ?
R = gas constant =
T =temperature =
0.025 moles of nitrogen gas are there in the sample.
Answer:
See the answer below
Explanation:
The chaparral biome is a temperate biome with a characteristic high temperature and dryness during summer and mild rainy winters and springs. The biome can be found in relatively small amounts in the major continents of the world with its rich plant and animal diversity who have successfully adapted to the conditions of the biome.
Due to the high biodiversity of the chaparral biome, <u>one would expect it to be resilient to the loss of a single species.</u> <em>The more the biodiversity of a biome or community, the more resilient such biome or community would be to the loss of species and lower the biodiversity, the more sensitive the community would be to the loss of species. </em>