First, we convert the weight of the infant to kg.
25 lb x (1 kg / 2.21 lb) = 11.31 kg
Then, we use the givens above for our dimensional analysis.
(11.31 kg)(10 mg/1 kg)(5.0 mL/100 mg) = 5.655 mL
Thus, the recommended amount in mL of the suspension should be 5.655 or approximately 5.7.
Tonight I’m Doing homework :(
Answer is 54 °C.
<em>Explanation;</em>
We can simply use heat equation
Q = mcΔT
Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Let's assume that the initial temperature is T.
Q = 5.53 × 10⁵ J
m = 2850 g
c = 4.186 J/g °C
ΔT = (100 - T) °C <em>Since the water is boiling, the final temperature is 100 °C.</em>
By applying the equation,
5.53 × 10⁵ J = 2850 g x 4.186 J/g °C x (100 - T) °C
(100 - T) °C = 5.53 × 10⁵ J / (2850 g x 4.186 J/g °C )
(100 - T) °C = 46.35 °C
T = 100 - 46.35 C = 53.65 °C
≈ 54 °C
I think it should be none of those
