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3 years ago

What is the molarity of a solution containing 45 grams of CaCl2 in 1.5 L of water?

Chemistry

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

Data:

Mass of solute: 45 g

m.mass of solute: 110 g/mol

volume of water: 1.5 L

Explanation:

percent w/v: 45/1500 *100

vol of solution: 3cm3=0.003dm3

M=g of solute/m.mass of solute*dm3 of sol

M= 45/110*0.003

M=14.85

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Answer:

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Explanation:

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$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{108.5 kPa}\qquad & V_{1} &= & \text{261 mL} \\p_{2}& =& \text{96.5 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}108.5 \times 261 & =& 96.5V_{2}\\28320 & = & 96.5V_{2}\\V_{2} & = &\dfrac{28320}{96.5}\\\\& = &\textbf{293 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{293 mL}}$

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Vinvika [58]

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3 years ago

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katrin2010 [14]

Answer:

The answer to your question is SrCrO₄ + H₂O

Explanation:

Data

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Then, for this reaction,

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Remembering that
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