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snow_lady [41]
3 years ago
7

What is the molarity of a solution in which 211g sodium hydrogen carbonate is dissolved in a 10.0L solution?​

Chemistry
1 answer:
siniylev [52]3 years ago
8 0

Answer:

0.25 M

Explanation:

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Which element is oxidized in the reaction below?<br> 2Na+ Br2 → 2NaBr
timama [110]

Answer:

Bromine

Explanation:

Br2 is an oxidizing agent, Na is a reducing agent.

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while looking at calcuim (Ca) on the periodic table a student needs to find with a greater atomic mass in the same period.Where
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To the right of calcium and in the same period.
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With regards to a “Data (Age) Structure Diagram”, which of the following is an indicator of a rapidly growing population?
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For a rapidly growing population is characterized by an increase in the number of young individuals, birth rates increased in comparison with mortality, and the age structure of the population gets the reproductive type In other words there is superiority of juveniles on the elderly and the relative decrease in mortality.


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3 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

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