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yawa3891 [41]
3 years ago
5

Calculate the heat energy needed to change the temperature of 2 kg of copper from 10C to 110C ​

Physics
1 answer:
Alina [70]3 years ago
7 0
Q = m c ΔT 

Q = (2)(385)(110 - 10) 

Q = 77000 Joules 
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A cubical wooden box floating on water rises 1cm when 400 gm of stone is
Ksivusya [100]

Answer:

Explanation:

I'm not  sure you can do this without just a bit more information. I can tell you what the mass of the water is when the rocks are removed. When we know that, we know the volume of the water that was displaced. whether or not this is enough information to determine the volume of the box, I'm not sure.

400 grams raises the box 1 cm.

The density of water = 1 gm / cm^3

400 grams of water = 400 mL or 400 cm^3

The volume of the displaced water = 400 cm^3

The volume a slice from the square prism is B*h

B = 400 cm^2

h = 1 cm

If the base is 400 cm^2 then each side is

s^2 = 400

sqrt(s^2)= sqrt(400)

s = 20

The volume of the box is 20^3 = 8000 cm^3

5 0
3 years ago
The main difference between the internal combustion engine and the diesel engine is that the diesel engine
NeTakaya
The diesel engine has no ignition system. (C)
It depends on the compression of the fuel/air mixture to ignite the mixture.

This may be a big part of the reason that Diesel engines always
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4 0
3 years ago
The mass of Jupiter is 1.9 × 1027 and that of the sun is 1.99 × 1030. The
n200080 [17]

Answer:

F = 4.147 × 10^23

v = 1.31 × 10^4

Explanation:

Given the following :

mass of Jupiter (m1) = 1.9 × 10^27

Mass of sun (m2) = 1.99 × 10^30

Distance between sun and jupiter (r) = 7.8 × 10^11m

Gravitational force (F) :

(Gm1m2) / r^2

Where ; G = 6.673×10^-11 ( Gravitational constant)

F = [(6.673×10^-11) × (1.9 × 10^27) × (1.99 × 10^30)] / (7.8 × 10^11)^2

F = [25.231 × 10^(-11+27+30)] / (60.84 × 10^22)

F = (25.231 × 10^46) / (60.84 × 10^22)

F = 3.235 × 10^(46 - 22)

F = 0.4147 × 10^24

F = 4.147 × 10^23

Speed of Jupiter (v) :

v = √(Fr) / m1

v = √[(4.147 × 10^23) × (7.8 × 10^11) / (1.9 × 10^27)

v = √32.3466 × 10^(23+11) / 1.9 × 10^27

v = √32.3466× 10^34 / 1.9 × 10^27

v = √17. 023 × 10^34-27

v = √17.023 × 10^7

v = 13047.221

v = 1.31 × 10^4

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3 years ago
paula finds four unlabeled containers of clear, odorless liquid in her laboratory storage. one of the containers holds water. sh
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The answer is c ............
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