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When the gas temperature decreases the volume decreases too.
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Answer:
4 times greater
Explanation:
<u>Step 1:</u> Calculate light-collecting area of a 20-meter telescope (A₁) by using area of a circle.
Area of circle = π*r² =
Where d is the diameter of the circle = 20-m


A₁ = 314.2 m²
<u>Step 2:</u> Calculate light-collecting area of a 10-meter Keck telescope (A₂)

Where d is the diameter of the circle = 10-m

A₂ = 78.55 m²
<u>Step 3</u>: divide A₁ by A₂

= 4
Therefor, the 20-meter telescope light-collecting area would be 4 times greater than that of the 10-meter Keck telescope.
In a constant acceleration of 3m per second, after 10 seconds,
3 x 10 = 30
B. 30m/s is your answer
hope this helps XD
He uses 63 watts.
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To determine the acceleration of the car, we use equation of motion
Here, v is final velocity of the car, u is the initial velocity of the car, a is the acceleration of the car in time t.
Given,
, u=0 because car accelerate from 0 and t = 3.40 s.
Substituting these values in above equation, we get

In mi/ h.s,
1 m = 0.000621371 mile.
1 s = (1/3600 ) hour = 0.000277778 hour.
Therefore,
