Answer:
Δv = vf - vi = 45 - 20 = 25 m/s
Explanation:
Answer:
1 is a great answer for this question
So the equation ask to calculate on how much can you lift using 1.4m long wheelbarrow that weighs 80n with its CG.5m from the center of the wheel and the weight will be 1740N. I hope you are satisfied with my answer and feel free to ask for more.
Explanation:
A. Up along the page
Using the law of the right hand
For part a we can use the kinematic formula distance= velocity(initial)*time+1/2*acceleration*time^2
we know there is only velocity in the horizontal and none in the vertical so v initial in this case is 0, acceleration is gravity =9.81m/s^2
plug in .95=(1/2)*9.81*t^2 solve for t
t=.44seconds
Now for part b we know there is no horizontal acceleration so distance= velcoity* time
we will use horrizontial velocity and the time we just found
distance= .8m/s*.44seconds
=.35 meters