A 1520 kg car is rolling
down a frictionless
14.4° slope. What is
its acceleration?
1 answer:
Answer:
a = 2.44 m/s²
Explanation:
The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.
Thus;
mg(sin θ) = ma
Thus;. g(sin θ) = a
g is acceleration due to gravity = 9.81 m/s²
θ = 14.4°
Thus;
9.81 × sin 14.4 = a
a = 2.44 m/s²
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