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Anarel [89]
2 years ago
9

A 1520 kg car is rolling down a frictionless 14.4° slope. What is its acceleration?

Physics
1 answer:
Umnica [9.8K]2 years ago
7 0

Answer:

a = 2.44 m/s²

Explanation:

The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.

Thus;

mg(sin θ) = ma

Thus;. g(sin θ) = a

g is acceleration due to gravity = 9.81 m/s²

θ = 14.4°

Thus;

9.81 × sin 14.4 = a

a = 2.44 m/s²

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