Question

A sample of helium gas has a volume of 1.25 L and a temperature of 22 °C, under a constant pressure. What is the new volume if the temperature is increased to 45 °C?

Answer 1

Answer:

the new volume is 1.35L

Explanation:

The computation of the new volume in the case when the temperature rises to 45 degrees is shown below:

GIven that

Volume = 1.25L

And, the temperature is 22 degrees celsius

So, $T_1$ = (275 + 22)k

= 297 k

Now

$T_2$ = (275 + 45)k

= 320 k

Now as it is a constant pressure

So, the new volume is

$\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1}{T_1}\times T_2 \\\\= \frac{1.25}{297}\times 320$

= 1.35L

hence, the new volume is 1.35L