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3 years ago

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Consider an ideal monatomic gas of N particles with mass m in thermal equilibrium at a temperature T. The gas is contained in a

cube of side L whose top and bottom are parallel to the Earth’s surface, and the gravitational acceleration is a constant g throughout the box. (a) What is the average kinetic energy of an atom of this gas?

1 answer:

harina [27]3 years ago

3 0

Answer:

$K.E.=\dfrac{3}{2}KT$

Explanation:

Given that

Number of particle =N

Equilibrium temperature= T

Side of cube = L

Gravitational acceleration =g

The kinetic energy of an atom given as

$K.E.=\dfrac{3}{2}KT$

Where

Equilibrium temperature= T

Boltzmann constant =K

K =1.380649×10−23 J/K

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