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Ierofanga [76]
3 years ago
12

The reaction between potassium hydroxide and sulfuric acid is given below. If you have 7.00 grams of KOH and 7.00 grams H2SO4, w

hat is the limiting reactant (2 points)? How much K2SO4 is made ​

Chemistry
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

i actualky dont know im sorry but when i figure out i will give it to you

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Calculate the pH of the resulting solution if 26.0 mL of 0.260 M HCl(aq) is added to:
enyata [817]
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
7 0
3 years ago
4. Know the location of metals, non-metals and metalloids
erastovalidia [21]

Answer:

The metals are to the left of the line (except for hydrogen, which is a nonmetal), the nonmetals are to the right of the line, and the elements immediately adjacent to the line are the metalloids.

Hope this helped

7 0
3 years ago
How is it possible for there to be more than one kind of atom of the same element?
tiny-mole [99]

They are called isotopes.

Isotopes have the same number of electrons and protons in their unionized state. They differ in the number of neutrons. The first and simplest example is hydrogen.


The most common hydrogen has

1 proton

1 electron and

0 neutrons


It has 2 cousins

1 proton

1 electron

1 neutron

And

1 proton

1 electron

2 neutrons.


Most elements have some differences in the number of neutrons present in their nuclei. Cesium and Xenon have the most number of isotopes. Each has 36. You wonder how the atoms are held together.


6 0
3 years ago
Read 2 more answers
Draw Conclusions does the F2 generation support that lack of wings is a genetic trait? Explain why or why not​
Dmitrij [34]

Answer:

An F1 offspring could produce four types of gametes, RY, Ry, rY, and ry. The F2 generation supports the independent-assortment model and refutes the linkage model.

Explanation:

3 0
3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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