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DerKrebs [107]
3 years ago
12

A sprinter generates a constant force of 52 N as he runs 100 m. How much work did he do?

Physics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0
You just multiply these two numbers. It's 5200J, or 5.2kJ
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Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.
masya89 [10]
V=r/t
Speed equals displacement over the time

V=100/9.92=10.08ms^-1
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3 years ago
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A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?
STatiana [176]
Power = Force * Distance/ time
P = 1,250 * 2/3
P = 2,500/3
P = 833.33 Watts

So, your final answer is 833.33 Watts
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3 years ago
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DIA [1.3K]

Answer:

sun, jupiter, earth, moon

Explanation:

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2 years ago
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Write a complete scientific explanation to account for why the ball that was moving faster caused more flour to spread out.​
Harlamova29_29 [7]

Answer:

It is due to the large impulse is imparted on the flour.

Explanation:

A ball is moving faster.

When a ball is moving faster strikes to the flour, the change in momentum is large and thus the impulse imparted on the flour is large.

Impulse = change in momentum

So, as the flour experiences large impulse and large momentum so that the flour spreads out.

If the change in momentum is large so the flour spreads out is more.  

8 0
3 years ago
A subway train starts from rest at a station and accelerates at a rate of 1.68 m/s2 for 14.2 s. It runs at constant speed for 68
liubo4ka [24]

Answer:

total distance = 1868.478 m

Explanation:

given data

accelerate = 1.68 m/s²

time = 14.2 s

constant time = 68 s

speed = 3.70 m/s²

to find out

total distance

solution

we know train start at rest so final velocity will be after 14 .2 s is

velocity final = acceleration × time      ..............1

final velocity = 1.68 × 14.2

final velocity = 23.856 m/s²

and for stop train we need time that is

final velocity = u + at

23.856 = 0 + 3.70(t)

t = 6.44 s

and

distance = ut + 1/2 × at²     ...........2

here u is initial velocity and t is time for 14.2 sec

distance 1 = 0 + 1/2 × 1.68 (14.2)²

distance 1 = 169.37 m

and

distance for 68 sec

distance 2= final velocity × time

distance 2= 23.856 × 68

distance 2 = 1622.208 m

and

distance for 6.44 sec

distance 3 = ut + 1/2 × at²

distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²

distance 3 = 76.90 m

so

total distance = distance 1 + distance 2 + distance 3

total distance = 169.37 + 1622.208 + 76.90

total distance = 1868.478 m

7 0
3 years ago
Read 2 more answers
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