Derived quantities depend on.( fundamental)..........physical quantity
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Answer:
Coefficient of friction between the book and floor is 0.582.
Explanation:
Using the velocity formula;
v^2 = 2as
a = v^2/(2s)
a = 1.6^2/(2*0.9)
a = 2.56/1.8
a = 1.42 m/s^2
the force necessary to give the book the acceleration is
F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)
F = 4.98 N
The difference in the force is the friction force, which is
Ff = 25 - 4.98 = 20 N
Ff = mgμ
where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2
μ = Ff/mg
μ = 20/(3.5*9.81)
μ = 0.582
Coefficient of friction between the book and floor is 0.582.
Rw/Ra = MA
18cm/2cm= MA
MA = 9
This means that Fi is 1/9 of the force applied to the axil. The distance travelled by Rw is 9 times more than Ri is that you move 9 times more when turning the wheel using Rw.
Put more simply
Rw/Ra = Fa/Fw
- Rw = Radius of the wheel
- Ra = Radius of the axil
- Fa = Force delivered on the axil
- Fw = Force delivered by the wheel
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I don’t know how to help you hope you figure it out have a good day