B. what does it mean to release a chemical?|

Physics

1 answer:

blsea [12.9K]3 years ago

3 0

(A "release" of a chemical means that it is emitted to the air or water, or placed in some type of land disposal.)

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A monkey weighs 6.00 x 102 N and swings from vine to vine. As the monkey grabs a new vine, both vines make an angle of 35.0° wit

zmey [24]

Answer:

$T=366.23\ N$

Explanation:

Given:

mass of monkey, $w=600\ N$

angle of vine from the vertical, $\theta=35^{\circ}$

Now follow the schematic to understand the symmetry and solution via Lami's theorem.

<u>The weight of the monkey will be balanced equally by the tension in both the vines:</u>

Using Lami's Theorem:

$\frac{w}{sin\ 70^{\circ}} =\frac{T}{sin\ 145^{\circ}}$

$\frac{600}{sin\ 70^{\circ}} =\frac{T}{sin\ 145^{\circ} }$

$T=366.23\ N$

4 0

4 years ago

A 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. Which of the following statements is true?

ella [17]

In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s

7 0

3 years ago

Read 2 more answers

The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross

Oksana_A [137]

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

<h3>What is gauge pressure?</h3>

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3 = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

$\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa$