Velocity of vw bug is given as
towards north
velocity of imphala is given as
towards south
now we need to find velocity of imphala relative to bug
so the speed is 101 mpH towards south so correct option is C
Di = two, just like 'bi'. --take di-zygotic twins, or di-atomic + di-sulphide, etc.
The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
<h3>Electric field on the master charge</h3>
E = kq/r²
where;
- q is magnitude of master charge
- r is distance of separation
- k is Coulomb's constant
E = (9 x 10⁹ x 0.63)/(0.75²)
E = 1.008 x 10¹⁰ N/C
<h3>Force on the test charge</h3>
F = Eq
where;
- E is electric field
- q is the test charge
F = (1.008 x 10¹⁰) x (0.5)
F = 5.04 x 10⁹ N
Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
Learn more about electric field here: brainly.com/question/14372859
#SPJ1
Answer:
I beleive its B
Explanation:
If not then A but I'm positive its B
Answer: 0
Explanation:
75 newtons will push back canceling it out make it 0
