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4 years ago

How do elements vary across a period

1 answer:

4 0

Answer: Elements in the same period have the same number of electron shells; moving across a period ( elements gain electrons and protons and become less metallic. This arrangement reflects the periodic recurrence of similar properties as the atomic number increases.

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Please write something What to do in case of a fire. ~write a few sentences~

Zarrin [17]

Follow stop drop and roll if the fire is in the room
Other wise exit immediately and find the nearest fire point. Then when you are out phone the fire services.
I hope this helps :)

5 0

3 years ago

Read 2 more answers

A large, 60 turn circular coil of radius 10.0 cm carries a current of 4.2 A. At the center of the large coil is a small 20 turn

Eddi Din [679]

To solve this problem we apply the concepts related to the electric torque generated by the electromagnetic field. Mathematically this Torque can be written under the following relation

$\tau = NIAB sin\theta$

Here,

N = Number of Turns

I = Current

A = Area

B = Magnetic Field

The maximum torque will be reached when the angle is 90 degrees, then we will have the following relation,

$\theta = 90\°C$

Magnetic Field is given at function of the number of loops, permeability constant at free space at the perimeter, then

$B = \frac{N\mu_0 I}{2\pi r}$

$B = \frac{(60)(4\pi * 10^{-7})(4.2)}{2\pi (0.1)}$

$B = 5.04*10^{-4}T$

Replacing at the first equation we have,

$T = (20)(\pi (0.005)^2)(1)(5.04*10^{-4})$

$T = 7.91*10^{-7}N\cdot m$

4 0

3 years ago

A vehicle with a mass of 2,553 kg accelerates at 10 m/s2. Find the force on the vehicle in Newtons.

Lerok [7]

Answer:

F = 25530 N

Explanation:

F(net) = ma

F(net) = 2553 kg•(10) m/s² = 25530 N

8 0

3 years ago

Which two energy sources can help a star maintain its internal thermal pressure? nuclear fission and gravitational contraction n

3241004551 [841]

Answer:

Nuclear fusion and gravitational contraction

Explanation:

In stars, there is an equilibrium between two forces, the force of gravity in the inward direction due to their own mass, and the radiation pressure in the upward direction as a consequence of the nuclear reaction in their core, that is known as hydrostatic equilibrium.

The radiation pressure is gotten from the nuclear reactions at the core (when lighter elements fuse into heavier elements), but if the nuclear reactions stop, hence, the radiation pressure will also do it and the force of gravity will overcome and break the equilibrium.

Both of that energy sources help to maintain a star's internal thermal pressure, since the contractions of the superficial layers will increase the density at the core.

5 0

4 years ago

Read 2 more answers

Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling

quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (Sp is for Spot, F is for Fido and St is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

$\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0$ (1)

$\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0$ (2)

If we know that $F_{F} = 20\,N$ , $F_{Sp} = 30\,N$ and $\theta_{F} = 63^{\circ}$ , then the components of the force done by Steinberg on the chewing toy is:

$F_{St,x} = -F_{F}\cdot \cos \theta_{F}$

$F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}$

$F_{St, x} = -9.080\,N$

$F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}$

$F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}$

$F_{St, y} = 12.180\,N$

The magnitud of the force is determined by Pythagorean Theorem:

$F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}$

$F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}$

$F_{St} \approx 15.192\,N$

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)$

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{12.180\,N}{-9.080\,N}\right)$

$\theta_{St} \approx 126.704^{\circ}$

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

5 0

3 years ago