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3 years ago

Substance B is found to be more viscous than substance A. This means that _____.

Physics

1 answer:

Aloiza [94]3 years ago

7 0

Answer: Option (2) is the correct answer.

Explanation:

Viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.

For example, honey has high viscosity.

Whereas a substance which has less viscosity is will be able to flow easily from one place to another.

For example, water has low viscosity.

So, when substance B is more viscous then it means it has high viscosity than substance A. Hence, substance B will flow slowly as compared to substance A.

Thus, we can conclude that substance B is found to be more viscous than substance A. This means that B flows slower at room temperature than A does.

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A force of 1750 n is exerted on a piston that has an area f 0.010 m2. What area is required for a second piston to exert a force

Natali5045456 [20]

Answer:

0.035 m2

Explanation:

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4 years ago

a wall of glass 2cm thickhas inside temperature of 30°C,outside temperature of15°C.how much heat is flowing through the glass(k=

kenny6666 [7]

Answer:46.5

Explanation:is the topical formula of F= 30x+15

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4 years ago

A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate

PilotLPTM [1.2K]

Answer:

$T(1)=21$

Explanation:

The equation of the position in kinematics is given:

$x(t)=x_{0}+v_{0}t+0.5at^{2}$

x(0) is the initial position, in this it is 0
v(0) is the initial velocity (20 m/s)
a is the acceleration (2 m/s²)

So the equation will be:

$x(t)=20t+0.5*2*t^{2}$

$x(t)=20t+t^{2}$

Now, the Taylor polynomial equation is:

$f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...$

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.

$f(t)=x(t)=20t+t^{2}$

$f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t$

$f''(t)=\frac{dv(t)}{dt}=a(t)=2$

Using the Taylor polynomial with a = 0 and take just the second order of the derivative.

$f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}$

$f(0)=x(0)=0$

$f'(0)=v(0)=20$

$f''(0)=a(0)=2$

$T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}$

$T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}$

$T(t)=20t+t^{2}$

Let's put t=1 so find the how far the car moves in the next second:

$T(1)=20*1+1^{2}$

$T(1)=21$

Therefore, the position in the next second is 21 m.

We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.

I hope it helps you!

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3 years ago

Which of the following statements is not true

mixer [17]

Answer:

The answer is the First One

Explanation:

Electromagnets can work with a magnetic source, and not just electric. sorry if my answer turns out to be wrong

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4 years ago

What is the molecular formula for the hydrocarbon in the mass spectrum above?

PtichkaEL [24]

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3 years ago