Answer:
(a) Charge density σ=6.6375×10²nC/m²
(b) Total charge Q=1.47×10²nC
Explanation:
Given Data
A=47.0 cm =0.47 m
Electric field E=75.0 kN/C
To find
(a) Charge density σ
(b)Total Charge Q
Solution
For (a) charge density σ
From Gauss Law we know that
Φ=Q/ε₀.......eq(i)
Where
Φ is electric flux
Q is charge
ε₀ is permittivity of space
And from the definition of flux
Φ = EA
The flux is electric field passing perpendicularly through the surface
Put the this Φ in equation(i)
EA
=Q/ε₀
where Q(charge)=σA
EA=(σA)/ε₀
E=σ/ε₀
σ=ε₀E
σ=6.6375×10²nC/m²
For (b) total charge Q
Q=σA
Answer:
3. you need to ask your available lab instructors what to do.
4. You immediately have to drop down your cloth and roll it to extinguish the fire or move to the emergency shower if available
5. You have too keep calm and report to the lab instructor but do no shout.
6. Move immediately to the eye rinse basin if available and wash your eyes gently and thoroughly
The Right Answer Is: <span>the high frequencies and shorter wavelengths penetrates body easily.</span>
Answer:
a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h
b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h
Explanation:
Now for (a)
time = velocity/distance
for velocity = 79.2 km/h and distance 0.0586 km
t = (0.0586/79.2)*3600
t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)
for velocity 47.8 km/h and distance 0.0242 km
t = (0.0242/47.8)*3600
t = 1.82 seconds
Now for (b)
2as = vf2-vi2
so,
2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)
a = -4.13 m/s2 for 58.6 m
and
2a(24.2) = -(47.8*1000/3600)^2
a = -3.63 m/s2 for 24.2 m.
Please note that "-" sign express the deceleration.
