Image<span> formed by a </span>plane mirror is<span> always </span>virtual<span> which means that the light rays </span>do<span> not actually come from the </span>image but<span> upright and these of the same shape and size are the object it </span>is<span> reflecting.</span>
Explanation:
The gravitational force between two objects when they are placed at some distance is given by :
Where
G is universal gravitational constant
m₁ and m₂ are masses
d is the distance between masses
The gravitational force is directly proportional to the product of masses and inversely to the square of the distance between them. It would mean that if the mass of the objects increases, the force will increase while if the distance is increased, the force between objects will decrease.
The correct answer to the question is - A). Light waves can travel in a vacuum and travel at a constant speed even if the light source is moving.
EXPLANATION:
Before going to answer this question, first we have to understand the fundamental postulate of quantum mechanics.
As per the fundamental postulate of quantum mechanics, the speed of light is always constant irrespective of the nature of frame of reference i.e speed of light is same both in inertial and non-inertial frame of reference. It is independent of the velocity of source also.
Again we know that light is an electromagnetic wave. Hence, it won't require any medium for its propagation. It can travel in space or vacuum also.
Hence, the correct option out of four options is that light waves can travel in a vacuum and travel at a constant speed even if the light source is moving.
Mechanical advantage = (output force) / (input force)
Mechanical advantage = (60 N) / (12 N)
Mechanical advantage = 5.0