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3 years ago

An electric travel blanket uses a car's 12V supply. The current is 3A.

1 answer:

5 0

For electrical devices . . .

   Power dissipated = (voltage) x (current) =

   (12 V) x (3.0 A) = 36 watts .

1 watt means 1 joule per second

   (36 joule/sec) x (60 sec/min) x (10 min) = 21,600 joules

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A nebula, or swirling cloud of interstellar dust and gases, is seen. What happens next in the star formation process?

AVprozaik [17]

Atoms begin to gravitate together to form a center

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4 years ago

Read 2 more answers

How come in free fall you feel weightless even though gravity is pulling down on you?

AysviL [449]

Feeling of Weight.

When walking, you feel the weight on your feet, therefore, your brain automatically refers to it as a source of weight.

In the air there is no platform to land on, therefore the brain does not have the conscience to register you getting pulled down.

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3 years ago

How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:

zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

$W=\Delta K$

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

$K=\frac{1}{2}mv^2$

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

$\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\ \\ \therefore K\approx532,346J \end{gathered}$

Therefore, the answer is: 532,346 J.

5 0

1 year ago

If the escalator pulls you up a slope of 30.0o and moves with a velocity of 3.10m/s. What is the vertical component of your v

ioda

Answer:

$1.55\ \text{m/s}$

$2.68\ \text{m/s}$

Explanation:

v = Velocity of the elevator = 3.1 m/s

$\theta$ = Angle of the slope = $30^{\circ}$

Vertical component is given by

$v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^{\circ}\\\Rightarrow v_y=1.55\ \text{m/s}$

The vertical component of the velocity is $1.55\ \text{m/s}$ .

Horizontal component is given by

$v_x=v\cos\theta\\\Rightarrow v_x=3.1\times \cos30^{\circ}\\\Rightarrow v_x=2.68\ \text{m/s}$

The horizontal component of the velocity is $2.68\ \text{m/s}$ .

8 0

3 years ago

a car traveling at 24 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds what is its acceleration?

Irina18 [472]

We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.

We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.

The following equation has everything we need:

$v_f=v_i + at$

So plug in the known values and solve for a:

0 = 24 + 6a

-24 = 6a

a = -4 m/s^2

8 0

4 years ago