1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artemon [7]
2 years ago
14

A rocket at rest with a mass of 942 kg is acted on by an average net force of 6,731 N upwards for 21 s. What is the final veloci

ty of the rocket?
Physics
1 answer:
Galina-37 [17]2 years ago
6 0

Answer:

Explanation:

Givens

m = 942

F = 6731

t = 21 seconds

vi = 0

vf = ?

Formula

F = m * (vf -  vi )  / t

Solution

6731 = 942*(vf - 0)/21          Multiply both sides by 21

6731 * 21 = 942*vf

141351 = 942*vf                   Divide by 942

141351/942 = vf

vf = 151 m/s

You might be interested in
Which of the following is the name of the process scientists use to gain
harkovskaia [24]

Answer:

b

Explanation:

.

6 0
3 years ago
What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2? (1 point)
aliya0001 [1]

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force applied on an object

m is the mass of the object

a is its acceleration

For the object in this problem,

m = 27 kg

a=11550 m/s^2

Substituting, we find the force required:

F=(27)(11550)=311,850 N

3 0
3 years ago
A 125 g pendulum bob hung on a string of length 35 cm has the same period as when the bob is hung from a spring and caused to os
Bingel [31]

Answer:

k = 3.5 N/m

Explanation:

It is given that the time period the bob in pendulum is the same as its time period in spring mass system:

Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}

\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}

where,

k = spring constant = ?

g = acceleration due to gravity = 9.81 m/s²

m = mass of bob = 125 g = 0.125 kg

l = length of pendulum = 35 cm = 0.35 m

Therefore,

k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\

<u>k = 3.5 N/m</u>

4 0
3 years ago
Which has a greater force: a semi-truck at rest or a moving bicycle?
Wittaler [7]

Although the semi truck certainly has a larger mass, it is not in motion and therefore does not have any momentum. The bicycle however has both mass and velocity and therefore has the larger momentum of the pair.

8 0
3 years ago
Read 2 more answers
When an object is in orbit, it is falling at the same rate at which the Earth is curving. Please select the best answer from the
olga2289 [7]

The statement “When an object is in orbit, it is falling at the same rate at which the Earth is curving” is true. The speed of a satellite orbiting the earth depends only on the mass of the earth and the mass of the satellite.

7 0
3 years ago
Other questions:
  • Two long straight wires carry currents perpendicular to the xy plane. One carries a current of 50 A and passes through the point
    11·1 answer
  • In winter why do water tanks start freezing from surface and not from bottom
    10·1 answer
  • A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl
    6·1 answer
  • A boy throws a ball upward with a speed v0 = 12 m/s. The wind imparts a horizontal acceleration of 0.4 m/s2 to the left. At what
    12·1 answer
  • Which of these changes would solidify a substance?
    7·1 answer
  • A virtual image produced by a lens is always
    13·2 answers
  • A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation. (1) the force of the ho
    8·1 answer
  • Question 15 of 15
    9·1 answer
  • A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls on the same object to the left. If the object has a
    13·1 answer
  • Ilang ektarya ang lawak na itinakda ni llda na maaaring gawin palaisdaan​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!