The image of the object is 8cm to the left of the lens (D)
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What is the image of an object?
The image of an object is said to be the location where light rays from that object intersect with a mirror by reflection.
It is calculated thus:
1÷v = 1÷f - 1÷u
<h3>How to calculate the image of an object</h3>
From the formula
1÷v = 1÷f - 1÷u
<h3>
Where </h3>
V = image distance fromthe object
U = object
f = focal length
Substitute the values
1÷v = 1÷8 - 1÷ 4
1÷v = - 1÷8
Make v the subject of formula
v = -8cm
Therefore, the image of the object is 8cm to the left of the lens (D)
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It goes from positive to negative
The correct option is D.
The critical angle is defined as the angle of incidence, which provides an angle of refraction of 90 degree. At any angle of incidence greater than the critical angle, all the light will totally reflected, resulting in total internal reflection.Thus, the critical angle is equal to the refractive index.
The magnitude and sign of the charge are 0.8 MC and negative respectively.
To find the answer, we need to know about the electric potential of a point charge.
<h3>What's the mathematical expression of the electric potential of a point charge?</h3>
- Mathematically, the electric potential at a distance 'r' from a point charge 'q' is given as (Kq)/r.
- K is the electrical constant with value 9×10^(-9) in vaccum.
<h3>What will be the magnitude and sign of a charge, if potential is -3.50V at 2mm?</h3>
From the expression of electric potential, charge is
q= (potential ×r)/K
= (-3.5×0.002)/ (9×10^(-9))
= -0.8 mega coulomb.
Thus, we can conclude that the magnitude and sign of the charge are 0.8 MC and negative respectively.
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J.J. Thomson discovered the electron, leading to the Plum Pudding model