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otez555 [7]
3 years ago
7

What of an object is given relative to an origin

Physics
2 answers:
icang [17]3 years ago
5 0
I believe it's slope.
Zinaida [17]3 years ago
4 0
If you asked me "Where are you ?" and I said "I'm 13 miles.", the next words out of your mouth would definitely be "Which way from where ?". The location/position of a place or object is always given relative to a known, agreed place.
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<span>Which is a gas at room temperature?
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Which of these results in kinetic energy of an object? (1 point)
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A camera phone called the iPhone X has an image sensor size of 5 mm and a focal length of 4 mm. How long of a selfie-stick must
azamat

Answer:

length of selfie-stick is 1.62 m

Explanation:

Given data

image size h1 = 5 mm = 5 ×10^{-3} m

focal length = 4 mm = 4 ×10^{-3} m

distance h2 = 2.032 m

to find out

How long of a selfie-stick

solution

here we find first magnification

that is M = h1 /h2

M = 5 ×10^{-3} / 2.032

M = 2.46 ×10^{-3}

and we know M = p/q

so p = Mq = 2.46 ×10^{-3} q

so we apply lens formula

1/f = 1/p - 1/q

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q = 1.622 m

so length of selfie-stick is 1.62 m

4 0
3 years ago
A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a th
Ket [755]
I think is 30m/s I am not sure
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Consider two stars that are identical (same size, temperature and luminosity). Star A is 10 pc away from us and Star B is 20 pc
Mkey [24]

Answer:

Star A would be brighter than Star B

Explanation:

The apparent brightness of a star as perceived on Earth is dependent on its temperature, size, luminosity and distance from the Earth. Apparent brightness is the visible brightness to the eye at the surface of the Earth, while luminosity is the true brightness at the surface of the star.

A hotter star will radiate more energy per second per meter square of surface area. A larger star will have a greater surface area for radiation of energy, thus increasing the luminosity. For two identical stars, the difference in apparent brightness will be dependent on their distances from Earth.

Brightness and distance from earth have an inverse square relationship.

brightness∝\frac{1}{distance^{2} }

Assuming the star is a point source of radiation, as distance from the source is increased, the radiation is distributed over a surface proportional to the distance form the source. As distance is further increased, the radiation is distributed over a larger surface area reducing the effective luminosity.

If one star (Star B) is twice as far from the earth as the first (Star A), the brightness of Star B will be \frac{1}{2^{2} } of Star A.

Thus, Star B will appear to be a quarter of the brightness of Star A. Or, Star A will appear to be 4 times as bright as Star B.

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