Ask question

Ask question

All categories

3 years ago

5

How to determine the group of an element based on an electron configuration

1 answer:

emmainna [20.7K]3 years ago

3 0

Answer:

You can easily predict the group of any element by it's valence shell configuration. If the valence e confgn is ns1 then it belongs to 1 group if it is ns2 then it is 2 group element. For p block elements it is 10+ no of es of ns& np. Eg. Cl 3s2 3p5. So group no is 17. For d block elements group no is equal to ns+ (n-1) d es. For e.g. Cr 4s1 3d5 . Group no is 6. For f block elements group no is always 3.

Explanation:

You might be interested in

How do you think climate change affected the strength of the hurricane?

Aleksandr [31]

It effected it because the hurricanes just kept growing bigger and bigger

5 0

2 years ago

On a scale 1-10 how pretty am I?

Readme [11.4K]

Answer:

10

Explanation:

ur pefrct no matter the inside or outside

5 0

3 years ago

Read 2 more answers

What is Chemistry????

prisoha [69]

Answer:

Chemistry is the scientific study of matter and its properties

Explanation:

hope it helps <3

mark me as brainliest

5 0

2 years ago

Read 2 more answers

Calculate the pH in an aqueous 0.120 M nitrous acid solution.

Anvisha [2.4K]

Answer:- pH is 2.14.

Solution:- Nitrous acid, $HNO_2$ is a weak acid so first of all we solve for $H_3O^+$ and then figure out the pH.

the equation is written as:

$HNO_2(aq)+H_2O(l)\leftrightharpoons H_3O^+(aq)+NO_2^-(aq)$

Initial concentration for the acid is given as 0.120 M. Let's say the change in concentration is x. Then the equilibrium concentrations would be as:

$HNO_2=0.120-x$

$H_3O^+$ = $x$

$NO_2^-$ = $x$

Ka for nitrous acid is $4.5*10^-^4$ and the equilibrium expression for this would be written as:

$Ka=\frac{[H_3O^+][NO_2^-]}{HNO_2}$

Let's plug in the values in it.

$4.5*10^-^4=\frac{(x)^2}{0.120-x}$

To make the calculations easy we could ignore $x$ for the bottom and the expression becomes:

$4.5*10^-^4=\frac{(x)^2}{0.120}$

On cross multiply:

$x^2=4.5*10^-^4*0.120$

On taking square root to both sides:

$x=7.3*10^-^3$

So, $[H_3O^+]=7.3*10^-^3M$

Now we could calculate the pH using the pH formula:

$pH=-log[H_3O^+]$

$pH=-log(7.3*10^-^3)$

pH = 2.14

So, the pH of 0.120M nitrous acid is 2.14.

8 0

2 years ago

Read 2 more answers

Which type of ion most likely will be formed by group 16 elements of the periodic table?

elena55 [62]

Either covalent or ionic... they are nonmetals meaning that the are a component in both types of compounds

4 0

3 years ago