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lys-0071 [83]
3 years ago
9

What will happen to the pressure inside a container of gas if some of the gas is allowed to escape? Select one: a. there will be

no effect on the pressure b. The pressure will increase c. the effect is impossible to determine d. The pressure will decrease
Chemistry
1 answer:
Sonbull [250]3 years ago
5 0
D. The pressure will decrease
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Elements are distinguished from each other by the number of protons present in their nuclei??
Kisachek [45]

False....................

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3 years ago
A bottle sitting on a table has no forces at all acting upon it.
solong [7]

Answer:

I'm a bit confused on where the question is. Perhaps re-write it in the comments? I'd love to help but this seems more like an answer than a question xD

Explanation:

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2 years ago
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Pls help!!<br>plz answer correctly!<br>will give the brainliest!<br>Urgent!!​
blagie [28]

a)

A: Copper

B: CuO

C: \mathrm{CuSO_4}

D: $\mathrm{CuCO_3}$

E: $\mathrm{CO_2}$

F: $\mathrm{Cu(NO_3)_2}$

b)

$\mathrm{CuO+ H_2SO_4}\rightarrow \mathrm{CuSO_4 + H_2O}$

c)

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3 years ago
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The Valence Electrons of an Atom of Which Element would feel a Greater Effective Nuclear Charge than the Valence?
kumpel [21]
The effective nuclear charge is an innate property of a specific element. It is the pull of force that an electron feels from the nucleus. It is related to the valence electron by the equation: Z* = Z-S, where Z* is the effective nuclear charge, Z is the atomic number and S is the shielding constant.

For the following elements in the choices, these are their values of Z*:

Aluminum - +12.591
Beryllium - +1.912
Hydrogen - +1
Carbon - +4

The effective nuclear charge of Boron is +3. Thus, the answers are  Aluminum and Carbon.
5 0
3 years ago
The molar solubility of pbi2 is 1.5 103 m.
Vsevolod [243]

Answer: -

Concentration of PbI₂ = 1.5 x 10⁻³ M

PbI₂ dissociates in water as

PbI₂ ⇄ Pb²⁺ + 2 I⁻

So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.

Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =

= 1.5 x 10⁻³ x 2 M

= 3 x 10⁻³ M

PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.

[Pb²⁺] = 1.5 x 10⁻³ M

So solubility product for PbI₂

Ksp = [Pb²⁺] x [ I⁻]²

=1.5 x 10⁻³ x (3 x 10⁻³)²

= 4.5 x 10⁻⁹

8 0
3 years ago
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