C is the answer it’s not d because mackerel does not eat tuna I’m not sure tho
Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
Answer:
32.1 g
Explanation:
Step 1: Write the balanced combustion reaction
C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O
Step 2: Calculate the moles corresponding to 97.4 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
97.4 g × 1 mol/44.01 g = 2.21 mol
Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide
The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol
Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀
The molar mass of C₄H₁₀ is 58.12 g/mol.
0.553 mol × 58.12 g/mol = 32.1 g
Adenine , guanine, cytosine and thymine
