Force = Mass * Acceleration
Rise in altitude is directly proportional to decrease in pressure
The earth's atmosphere has its own pressure known as atmospheric pressure.The pressure level is highest right at the surface of the earth because the air at this level is supporting the weight of all the air above it. More weight above means a greater downward gravitational force. As we move up through levels of the atmosphere, the air has less air mass above it and gravity isn’t strong enough to pull down a greater number of particles. So the balancing pressure decreases. This is why atmospheric pressure drops as we rise in altitude.
During its lifepsan, the sun's core would keep contracting and heating up.
The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
Answer:
(a) ![v=22.177\times 10^{12}\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D22.177%5Ctimes%2010%5E%7B12%7D%5C%20m.s%5E%7B-1%7D)
(b) ![B=420.855\ T](https://tex.z-dn.net/?f=B%3D420.855%5C%20T)
(c) ![f=11.7647\times 10^{14}\ Hz](https://tex.z-dn.net/?f=f%3D11.7647%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
(d) ![T=8.5\times 10^{-14}s](https://tex.z-dn.net/?f=T%3D8.5%5Ctimes%2010%5E%7B-14%7Ds)
Explanation:
Given:
Kinetic Energy of an electron, ![KE=1.4\ keV=1400\ eV=1400\times 1.6\times 10^{-19}\ J](https://tex.z-dn.net/?f=KE%3D1.4%5C%20keV%3D1400%5C%20eV%3D1400%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%20J)
radius of the orbit, ![r=0.3\ m](https://tex.z-dn.net/?f=r%3D0.3%5C%20m)
we have:
mass of an electron, ![m=9.109\times 10^{-31}\ kg](https://tex.z-dn.net/?f=m%3D9.109%5Ctimes%2010%5E%7B-31%7D%5C%20kg)
charge on an electron, ![q=1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
(a)
we know:
![KE=\frac{1}{2} m.v^2](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B1%7D%7B2%7D%20m.v%5E2)
![1400\times 1.6\times 10^{-19}=0.5\times (9.109\times 10^{-31})\times v^2](https://tex.z-dn.net/?f=1400%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%3D0.5%5Ctimes%20%289.109%5Ctimes%2010%5E%7B-31%7D%29%5Ctimes%20v%5E2)
![v=22.177\times 10^{12}\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D22.177%5Ctimes%2010%5E%7B12%7D%5C%20m.s%5E%7B-1%7D)
(b)
<em>We also have the relation after the comparison of forces(centripetal and magnetic) on a moving charge in a magnetic field as:</em>
...........................(1)
where:
B = magnetic field normal to the plane of circulating charge
putting respective values in eq. (1)
![(9.109\times 10^{-31})\times (22.177\times 10^{12})=(1.6\times 10^{-19})\times 0.3\times B](https://tex.z-dn.net/?f=%289.109%5Ctimes%2010%5E%7B-31%7D%29%5Ctimes%20%2822.177%5Ctimes%2010%5E%7B12%7D%29%3D%281.6%5Ctimes%2010%5E%7B-19%7D%29%5Ctimes%200.3%5Ctimes%20B)
![B=420.855\ T](https://tex.z-dn.net/?f=B%3D420.855%5C%20T)
(d)
angular speed:
![\omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
![\omega=\frac{22.177\times 10^{12}}{0.3}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B22.177%5Ctimes%2010%5E%7B12%7D%7D%7B0.3%7D)
![\omega=73.92\times 10^{12}\ rad.s^{-1}](https://tex.z-dn.net/?f=%5Comega%3D73.92%5Ctimes%2010%5E%7B12%7D%5C%20rad.s%5E%7B-1%7D)
∴Time taken for 1 radian:
![t=\frac{1}{\omega}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B1%7D%7B%5Comega%7D)
![t=\frac{1}{73.92\times 10^{12}}\ s.rad^{-1}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B1%7D%7B73.92%5Ctimes%2010%5E%7B12%7D%7D%5C%20s.rad%5E%7B-1%7D)
Now time take for 1 circulation i.e. 2π radians(Time period):
![T=2\pi\times t](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Ctimes%20t)
![T=2\pi\times \frac{1}{73.92\times 10^{12}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Ctimes%20%5Cfrac%7B1%7D%7B73.92%5Ctimes%2010%5E%7B12%7D%7D)
![T=8.5\times 10^{-14}s](https://tex.z-dn.net/?f=T%3D8.5%5Ctimes%2010%5E%7B-14%7Ds)
(c)
we know frequency :
![f=\frac{1}{T}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7BT%7D)
![f=\frac{1}{8.5\times 10^{-14}}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B8.5%5Ctimes%2010%5E%7B-14%7D%7D)
![f=11.7647\times 10^{14}\ Hz](https://tex.z-dn.net/?f=f%3D11.7647%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
18:4 can be written as
9:2<---- when reduced