Answer:
<em>The volume of water is 3.5 cubic meter</em>
Explanation:
<u>Density </u>
The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.
The formula to calculate the density of a substance of mass (m) and volume (V) is:
We are given the density of water as .It's required to find the volume of m=3,500 kg of water. Solving for V:
The volume of water is 3.5 cubic meter
Answer: 39.8 μC
Explanation:
The magnitude of the electric field generated by a capacitor is given by:
d is the distance between the plates.
For a capacitor, charge Q = CV where C is the capacitance and V is the voltage.
where A is the area of the plate and ε₀ is the absolute permittivity.
substituting, we get
It is given that the magnitude of the electric field that can exist in the capacitor before air breaks down is, E = 3 × 10⁶ N/C.
radius of the plates of the capacitor, r = 69 cm = 0.69 m
Area of the plates, A = πr² = 1.5 m²
Thus, the maximum charge that can be placed on disks without a spark is:
Q = E×ε₀×A
⇒ Q = 3 × 10⁶ N/C × 8.85 × 10⁻¹² F/m × 1.5 m² = 39.8 × 10⁻⁶ C = 39.8 μC.
Explanation:
Using table A-3, we will obtain the properties of saturated water as follows.
Hence, pressure is given as p = 4 bar.
= 2553.6 kJ/kg
At state 2, we will obtain the properties. In a closed rigid container, the specific volume will remain constant.
Also, the specific volume saturated vapor at state 1 and 2 becomes equal. So,
According to the table A-4, properties of superheated water vapor will obtain the internal energy for state 2 at and temperature
so that it will fall in between range of pressure p = 5.0 bar and p = 7.0 bar.
Now, using interpolation we will find the internal energy as follows.
= 2963.2 - 2.005
= 2961.195 kJ/kg
Now, we will calculate the heat transfer in the system by applying the equation of energy balance as follows.
Q - W = ......... (1)
Since, the container is rigid so work will be equal to zero and the effects of both kinetic energy and potential energy can be ignored.
= 0
Now, equation will be as follows.
Q - W =
Q - 0 =
Q =
Now, we will obtain the heat transfer per unit mass as follows.
= (2961.195 - 2553.6)
= 407.595 kJ/kg
Thus, we can conclude that the heat transfer is 407.595 kJ/kg.