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loris [4]
3 years ago
12

What mass of hcl in grams is required to react with 0.750 g of al(oh)3?

Chemistry
1 answer:
tiny-mole [99]3 years ago
3 0
The mass would be 53
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How many atoms of S are there in the reactants?<br> Sg + F2 ---&gt; SFO
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Answer:

One atom

Explanation:

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What is the molality of a solution
vitfil [10]
Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution: Molarity (M) = moles solute. liters solution.
5 0
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"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"
Salsk061 [2.6K]

Answer:- The Ka for the acid is 1.53*10^-^5 .

Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

I 0.25 0 0

C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

Ka = [H^+][A^-]\frac{1}{HA}

Where, Ka is the acid ionization constant. Let's plug in the values.

Ka = \frac{X^2}{0.25-X}

Let's calculate the value of X first using the equation:

pH = -log[H^+][/tex]

on taking antilog ob above equation we get:

[H^+]=10^-^p^H

[H^+]=10^-^2^.^7^1

[H^+] = 0.00195

So, X = 0.001195

Let's plug in this value of X in the equation:-

Ka=\frac{(0.00195)^2}{0.25-0.00195}

Ka=1.53*10^-^5

So, the value of Ka for butyric acid is 1.53*10^-^5 .

8 0
3 years ago
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The alkline earth metals include?
patriot [66]

Answer:

The Popular ones are five in number

Explanation:

Calcium

Silicon

Germanium

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Lead

5 0
3 years ago
If you have 6.25g of O2, how many moles of H2O are produced?
denis23 [38]

Answer:

0.4 moles of water produced by 6.25 g of oxygen.

Explanation:

Given data:

Mass of oxygen = 6.25 g

Moles of water produced = ?

Solution:

Chemical equation;

2H₂ + O₂  → 2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 6.35 g/ 32 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of oxygen with water:

                    O₂          :          H₂O

                     1            :            2

                   0.2          :        2×0.2 = 0.4 mol

0.4 moles of water produced by 6.25 g of oxygen.

8 0
3 years ago
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