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3 years ago

What kind of energy can be mainly excited by us/visible light

Chemistry

1 answer:

erica [24]3 years ago

3 0

I'm thinking the answer you are looking for is light energy. With the sunlight there is light energy and heat.

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The name of an oxyacid has the suffix -ous acid. What is the suffix of the oxyanion?

Dima020 [189]

Answer:

-ate

Explanation:

6 0

3 years ago

What is the difference between Mitosis and Meiosis?

kondor19780726 [428]

Mitosis produces two diploid (2n) somatic cells that are genetically identical to each other and the original parent cell, whereas meiosis produces four haploid (n) gametes that are genetically unique from each other and the original parent (germ) cell.

7 0

3 years ago

3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with

ira [324]

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

7 0

3 years ago

Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan

natka813 [3]

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

Ag2SO4 ↔ 2Ag+ + SO42-

S 2S S...............in the equilibrium

Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

4 0

3 years ago

The solubility of kL is 50g in 100 g h2o at 20 celcius. If 110 grams of of kL are added to 200 grams of h2o. What is happens ?

tia_tia [17]

Answer:

a saturated solution will form.

Explanation:

All solutions have a definite capacity of dissolving solute in it.

Unsaturated solutions are the solutions which contain less amount of solute than the maximum capacity of dissolving the solute. If more amount of solute is added in such a way a point is reached where addition of more solute cannot be dissolved. The solution is known as saturated solution.

Amount dissolved > Maximum solubility limit, the solution is saturated.

Amount dissolved < Maximum solubility limit, the solution is unsaturated.

If the amount of the salt exceeds the solubility limit, then the solution is saturated solution. If it is less than the limit given, then it is unsaturated solution.

Given,

50 g of KI is added to 100 g of water at 20 °C.

It means:

100 g of water can dissolve maximum of 50 g of KCl.

Also,

1 g of water can dissolve maximum of 0.5 g of KCl.

To check for 200 g of water:

200 g of water can dissolve maximum of (0.5)*200 g of KCl.

Maximum amount of KCl that can be dissolved = 100 g

Actual amount dissolved = 110 g

Since,

Amount dissolved > Maximum solubility limit

110 g > 100 g

According to definition, the solution is saturated.

<u>Hence, a saturated solution will form.</u>

3 0

3 years ago