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3 years ago

Which statement about ocean surface currents is false?

Physics

1 answer:

Alla [95]3 years ago

4 0

A) they have no effect on air temperature over land on the coast is False

Explanation:

warm and cold ocean currents can influence the coastal areas only when the air is blown into the land from the sea.
the temperature over the land increases when warm ocean currents heat the air above the ocean.
the temperature over the land decreases when cold ocean currents cool the air above the ocean and can bring colder winds to the coastal regions.
so, ocean currents play a major role in regulating the air temperature over land on the coastal region.

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Which one of the following statements is true? Explain.

Makovka662 [10]

Answer:

All the given option is false.

Explanation:

This is not true for all the materials like composite because the Poisson ratio for composite material can be negative that is why positive tensile stress may produce positive lateral strain.

This is not true for all the material because the Poisson ratio for some material can be positive that is why positive tensile stress may produce negative lateral strain.

The explanation is same as option A.

This is not true for all the materials ,It is valid only up to elastic limit .After the elastic limit the strain and stress does not follow linear path.

This is not true for all the materials because some materials like composite is having negative value of Young's modulus.

Therefore all the given option is false.

5 0

3 years ago

A 50-kg toboggan is coasting on level snow. As it passes beneath a bridge, a 20-kg parcel is dropped straight down and lands in

timama [110]

Answer:

$KE2/KE1=0.71$

Explanation:

By conservation of the linear momentum:

m1*V1 = (m1+m2)*V2

Solving for V2:

$V2 = \frac{m1}{m1+m2}*V1$

The kinetic energies are:

$KE1=1/2*m1*V1^2$

$KE2 = 1/2*(m1+m2)*V2^2$

$KE2 = 1/2*(m1+m2)*(\frac{m1}{m1+m2}*V1)^2$

Simplifying:

$KE2 = 1/2*\frac{m1^2}{m1+m2}*V1^2$

The ratio will be:

$KE2/KE1=\frac{1/2*\frac{m1^2}{m1+m2}*V1^2}{1/2*m1*V1^2} =\frac{m1}{m1+m2}$

$KE2/KE1=0.71$

5 0

3 years ago

Suppose that a public address system emits sound uniformly in all directions and that there are no reflections. The intensity at

dybincka [34]

Answer:

The intensity at a spot 71 m away is $4.02*10^{-5} Wm^{-2}$

Explanation:

Given:

Initial intensity, $I_{1}=3.0*10^{-4} Wm^{-2}$ at a distance, $d_{1} = 26 m$

Required:

New intensity, $I_{2} =?$ at a distance, $d_{2} = 71 m$

Using the inverse square law,

I ∝ $\frac{1}{d^{2} }$

⇒ $I_{1}$ $I_{1}d_{1}^{2} =I_{2}d_{2}^{2}$

$I_{2} =\frac{I_{1} d_{1}^{2} }{d_{2}^{2}} =\frac{3.0*10^{-4}*26^{2} }{71^{2} } \\$ ×

$I_{2}=4.02*10^{-5} Wm^{-2}$

Thus, the intensity at a spot that is 71 m away is $4.02*10^{-5} Wm^{-2}$

5 0

3 years ago

A student finds an unlabeled bottle of liquid under

s344n2d4d5 [400]

Answer:

C. Adding some of the unknown liquid to red litmus paper.

Explanation:

Since the student doesn't know what the liquid is, it is not safe to experiment with it by boiling, cooling, or adding water to it. The safest option would be to add a small bit of the liquid to the litmus paper, which will identify the liquid as neutral, basic, or acidic.

6 0

3 years ago

Read 2 more answers

The R.I.C.E. procedure is useful for

balandron [24]

R.I.C.E. – Rest, Ice, Compression, And Elevation Procedure Explained. One of the most used treatments to assist with a sprain or a strain is the “RICE” method. As always, consult a doctor before attempting to do anything yourself if you are not sure of the severity of your strain or sprain.

5 0

3 years ago