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lakkis [162]
3 years ago
12

The Doppler shift can be observed when ____________. Check all that apply. Group of answer choices the source of sound moves tow

ards an observer the source of sound moves away from an observer an observer moves towards a stationary sound source an observer moves away from a stationary sound source the observer and sound source move at the same speed in the same direction the observer and sound source move at the same speed towards one another none of these
Physics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

the source of sound moves towards an observe

Explanation:

The Doppler effect is related to waves such as sound or light. the effect causes an increase or decrease in the frequency of sound light or other waves when the souces either move towards or away from the observer. For example the siren of the train to a person on the platform, the redshift seen by astronomers.

Therefore, The Doppler shift can be observed when the source of sound moves towards an observer From a place closer to the observer than the last wave's crest, each consecutive wave crest is sent. Each wave therefore, takes a little less time than the preceding wave to reach the observer.

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A 0. 25 kg baseball is in contact with a bat for 0. 0075 s and exerts a force of 18,500 n. What impulse is delivered to the ball
faust18 [17]

Answer:

I = 138.75N*s

Explanation:

I = F*t

I = Impulse or momentum

t = Time or duration

F = Force

I = 18,500N*0.0075s

I = 138.75N*s

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How is gamma rays used to transfer energy?
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4 years ago
Identify the correct order of increasing intermolecular force of attraction for the three most common states of matter.
professor190 [17]
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3 0
4 years ago
Read 2 more answers
A grocery cart of mass 16 kg is being pushed at a constant speed up a 12-degree ramp by a force of [{MathJax fullWidth='false' f
lawyer [7]

Answer:

If the cart is being pushed at a constant speed, then the acceleration in the direction of motion is zero. Hence, the force in the direction of the motion is zero, according to Newton's Second Law.

\Sigma F_x = ma_x

For simplicity, I will denote the direction along the inclined ramp as x-direction.

In the question the value of the force is not clearly given, so I will denote it as F_P

\Sigma F_{net_x} = ma_x\\\Sigma F = F_{P}\cos(29^\circ) - mg\sin(12^\circ) = ma_x = 0\\F_{P}\cos(29^\circ) = mgsin(12^\circ)\\F_{P}\times 0.8746 = 16\times 9.8\times  0.2079\\F_{P} = 37.2740

Here the angle between the applied force and the x-direction is 12° + 17° = 29°

The x-component of the weight of the cart is equal to sine component of the weight.

Since the cart is rolling on tires the kinetic friction does no work.

Work done by the applied force:

W_{F_P} = F_P_x \cos(29^\circ)\times 7.5 = 244.5 ~J

Work done by the weight of the cart:

W_{mg} = -mg\sin(12^\circ)\times 7.5 = -16\times 9.8 \times 0.2079 \times 7.5 = - 244.5~J

Since the x-component of the weight is in the -x-direction, its work is negative.

Conveniently, the total work done on the particle is zero, since its velocity is constant.

5 0
3 years ago
In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 54 minutes.
lawyer [7]

The frequency of the oscillation in hertz is calculated to be 0.00031 Hz.

The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.

So;

Period(T) = 54 minutes or 3240 seconds

Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz

Learn more: brainly.com/question/14588679

6 0
2 years ago
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