A certain speed boat weighs 4,283 N. It can accelerate from 0 to 20 m/s in 5 seconds. What is the mass of the boat?

Jaipal measures a circuit at 1.2 A and 24 . Using Ohm’s law, what can he calculate for the circuit? current (C) current (I) volt

jenyasd209 [6]

Answer: voltage (V)

Explanation:

Hi, in the answer the letter A (1.2 A) stands for Ampere, and the symbol next to the number 24 must be Ω 8 (Ohms)

So, applying Ohm's law:

Voltage (V) =current (I) x resistance (R)

V = I x R

Replacing with the values given;

V = 1.2 A x 24Ω

In conclusion, we can calculate the value of Voltage for the circuit.

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Read 2 more answers

A sugar cube placed in cold water will not dissolve True or false

sasho [114]

Answer:

False, it will just dissolve slowly

5 0

3 years ago

Read 2 more answers

PLEASE HELLPPP ITS FIR A FINAL 3.Speed (v) abs wavelength ( λ ) and the frequency (f) of sound are related asRequired to answer.

Aliun [14]

Answer:

B. v = λ X f

Hope this helps! 

8 0

3 years ago

A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen

Liula [17]

Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

$d \times \dfrac{y_m}{L}=m\lambda$

for (m+1)th order maxima

$d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda$

now,

$y_m=\dfrac{mL\lambda}{d}$ and

$y_{m+1}=\dfrac{(m+1)L\lambda}{d}$

hence,

$\Delta y = y_{m+1} - y_m$

$\Delta y =\dfrac{L\lambda}{d}$

$\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}$

$\Delta y =0.15\ m$

$\Delta y =15\ cm$

hence, the correct answer is option D

4 0

4 years ago

A copper cylinder has a mass of 76.8 g and a specific heat of 0.092 cal/g.C. It is heated to 86.5 degrees C from 19.5 degrees C.

Sladkaya [172]

Given:

The mass of the copper cylinder is: m = 76.8 g = 0.0768 kg

The change in the temperature is: T = 86.5 deg C - 19.5 deg C = 67 deg C

The specific heat is: c = 0.092 cal/g.C

To find:

Heat energy needed to heat the copper cylinder.

Explanation:

The specific heat is defined as the amount of heat energy needed to raise the temperature of a substance by one degree celcius.

The expression relating heat Q, mass m, specific heat c and temperature difference T is:

$Q=mcT$

Substitute the values in the above equation, we get:

$\begin{gathered} Q=76.8\text{ g}\times0.092\text{ Cal/g.C}\times67\text{ deg C} \\ \\ Q=473.40\text{ Cal} \end{gathered}$

Final answer:

473.40 calories of heat is required to heat the copper cylinder.

6 0

1 year ago