How many paddles should be on a water wheel?

noname [10]

Mutualism is a long-term relationship where two organisms interact in such a way that both of them benefits from that relationship.

For example, there is a relationship between a bird called "oxpecker", and a rhino. While the bird eats the harmful bugs (eg. tick) on the rhino's skin and relieves its hunger; the rhino gets rid of the bugs that harm it.

5 0

3 years ago

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A. Draw the electric field lines around a negative charge.

Alborosie

<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric fields, so this helps us to see the problem more real. So an electric field line is an imaginary line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. </em>This can be expressed as follows:

$F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m$

Then:

$F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}$

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

$q_{1} \ and \ q_{2}$

If the amount of charge on one of the objects is tripled, let's say this is the charge $q_{2}$ , then the new charge is:

$q_{N}=3q_{2}$

In the formula of Coulomb:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}$

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2}$

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod repels positive charges on the sphere, creating zones of negative and positive charge as indicated in the second Figure.

7 0

3 years ago

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Describe the movement on the distance / time graph.

love history [14]

The distance increases per minute, levels out, then continued increasing.

8 0

3 years ago

A hockey puck with mass 0.200 kg traveling east at 10.0 m/s strikes a puck with a mass of .250 kg heading north at 20 m/s and st

love history [14]

Answer:

4.44 i + 11.11 j , 11.96 m/s

Explanation:

m1 = 0.2 kg, v1 = 10 m/s along X axis, v1 = 10 i

m2 = 0.25 kg, v2 = 20 m/s along north, v2 = 20 j

After collision they stick together and let they move with velocity v.

Use the conservation of momentum

m1 x v1 + m2 x v2 = (m1 + m2) x v

0.2 x (10 i) + 0.25 x (20 j) = (0.2 + 0.25) x v

2i + 5j = 0.45 v

v = 4.44 i + 11.11 j

magnitude of velocity = $\sqrt{(4.44)^{2}+(11.11)^{2}}$ = 11.96 m/s

Thus, the velocity of 0.250 kg hockey puck is 4.44 i + 11.11 j metre per second and the magnitude of velocity is 11.96 m/s.

6 0

3 years ago

270000 round into 2 significant figures<br><br>270000 round into 3 significant figures

andrew-mc [135]

Answer:

270000 round into 2 significant figures

= 2.7 × 10⁵

Thus, 2 and 7 are significant figures.

270000 round into 3 significant figures

= 2.70 × 10⁵

Thus, 2, 7 and 0 are significant figures.

<u>-</u><u>TheUnknownScientist</u>

7 0

3 years ago