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matrenka [14]
3 years ago
13

At oxnard university, a student id consists of two letters (26 possibilities) followed by four digits (10 possibilities). (a) ho

w many unique student ids can be created?
Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Solution:\hbox{we have given that the combination is 2 letters and 4 digits}\\\rm{so}\\\hbox{the total number of unique combination should be the product of each possibilities}\\\hbox{therefore, the possibilities is:}\\\hbox{Total unique ID'S}=26\times26\times10\times10\times10\times10;\\\hbox{It can also be written as}\\\hbox{Total unique ID'S}=26^{2}\times10^{4}\\\hbox{this is the required possibilities.}

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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
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Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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In which

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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

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So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

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