Answer:
The correct option is;
B. 8 m, because he has to apply less force over a greater distance
Explanation:
In the given question, in order for the student to lift the boxes onto the tuck with less amount of force, he applies the principle of Mechanical Advantage
The mechanical advantage is given by the measure by which a force is amplified through the use of a tool
Given that the work done = The force × The distance, we have
F₁ × d₁ = F₂ × d₂, which gives;
d₁/d₂ = F₂/F₁
Where;
F₁ = The input force
F₂ = The output force
d₁ = The input distance
d₂ = The output distance
The Mechanical advantage, MA = d₁/d₂ = F₂/F₁
Therefore, when the input distance is increased the input force will be reduced for a given output force
46.58m/s²
26.43kg
Explanation:
Given parameters:
Force = 67N force = 185N
Mass = 1.43kg acceleration = 7m/s²
Unknown:
Acceleration = ?
mass of the object = ?
Solution:
According to newton's second law of motion "the net force on a body is a product of its mass and acceleration".
Force = mass x acceleration;
For the first problem;
the unknown is the acceleration;
Acceleration = = = 46.58m/s²
Using the same law, to find the mass of the second object, we make it the subject of the formula;
mass =
mass = = 26.43kg
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Answer:
The magnitudes of the speed and acceleration of the Earth are approximately 66,661.217 miles per hour and 47.782 miles per square hour, respectively.
Explanation:
Given that the Earth has a circular orbit and make a revolution at constant speed around the Sun. Then, the kinematic formulas for the speed and acceleration of the planet are, respectively:
Speed
(1)
Acceleration
(2)
Where:
- Speed of the planet, measured in miles per hour.
- Acceleration of the planet, measured in miles per square hour.
- Radius of the orbit, measured in miles.
- Period of rotation, measured in hours.
If we know that and , then the magnitudes of the speed and acceleration of the planet is:
The magnitudes of the speed and acceleration of the Earth are approximately 66,661.217 miles per hour and 47.782 miles per square hour, respectively.
Answer:
(A)
(B) s = 146.664 m
Explanation:
We have given car starts from the rest so initial velocity u = 0 m /sec
Final velocity v = 88 km/hr
We know that 1 km = 1000 m
And 1 hour = 3600 sec
So
Time is given t = 12 sec
(A) From first equation of motion v = u+at
So
So acceleration of the car will be
(b) From third equation of motion
So
s = 146.664 m
Distance traveled by the car in this interval will be 146.664 m
Resolution in this sentence refers to a solution to the problem