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vekshin1
3 years ago
5

A table of the visible light spectrum is shown below. A 2 column table with 6 rows. The first column is labeled color with entri

es red, orange, yellow, green, blue, purple. The second column is labeled wavelength in nanometers with entries 700 to 635, 635 to 590, 590 to 560, 560 to 490, 490 to 450, 450 to 400. Tyrone analyzes the emission spectrum of an unknown element. He observes two discrete lines at 600 nm and 650 nm, and he sees many lines corresponding to shorter wavelengths, with the strongest line being at 475 nm. Which emission spectrum is Tyrone most likely analyzing?
Physics
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

- The 600 nm wavelength corresponds to the orange zone of the visible light spectrum.

- The 650 nm wavelength corresponds to the red zone of the visible light spectrum.

- The lines corresponding to shorter wavelengths lower than the 475 nm include the purple and blue zone of the visible light spectrum.

Explanation:

The different parts of the visible light spectrum and their wavelengths is given as

red - 700 to 635

orange - 635 to 590

yellow - 590 to 560

green - 560 to 490

blue - 490 to 450

purple - 450 to 400

Note that all.of the wavelengths are given in nanometers.

He then observes two discrete lines at 600 nm and 650 nm.

The 600 nm wavelength corresponds to the orange zone of the visible light spectrum.

The 650 nm wavelength corresponds to the red zone of the visible light spectrum.

- And he sees many lines corresponding to shorter wavelengths, with the strongest line being at 475 nm.

The lines corresponding to shorter wavelengths lower than the 475 nm include the purple and blue zone of the visible light spectrum.

Hope this Helps!!!

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