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Feliz [49]
3 years ago
11

Two planets orbit a far away star as shown. Is it possible that both planets experience the same gravitation force from the star

?
A) No, it is not possible.
B) Yes, it is possible if the closer planet has less mass.
C) Yes, it is possible if the closer planet as a smaller radius.
D) Yes, it is possible if the closer planet orbits the star in a shorter time.

Physics
1 answer:
Vesna [10]3 years ago
8 0

As we know that gravitational force on two planets will be given as

let

mass of star = M

mass of two planets are m1 and m2

their distance from star is r1 and r2

F = \frac{GMm_1}{r_1^2} = \frac{GMm_2}{r_2^2}

since the gravitational force of star is given on two planets to be same

so here we can say

\frac{m_1}{r_1^2} = \frac{m_2}{r_2^2}

now if the ratio of mass and distance is same then we can say that closer planet must have lesser mass to hold good for above equation

so correct answer will be

B) Yes, it is possible if the closer planet has less mass.

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Calculate the binding energy per nucleon of the helium nucleus 52he. express your answer in millions of electron volts to four s
Vitek1552 [10]
The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
                                                        mn=mass of neutron=<span>1.67 10^-27 kg
                                                        </span><span>m nucleus= 5
Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5=  - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19=  -5.625 10^35 eV

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8 0
3 years ago
A certain runner averages 4.1 m/s over a 10
Ghella [55]

Answer: 40.650406504065 or 40 minutes and 39 seconds.

Explanation:

1 k = 1000m

race = 10000m

runner time = 10000 / 4.1

runner time = 2439.0243902439024 seconds

runner time = 2439.0243902439024/60 = 40.650406504065 or 40 minutes and 39 seconds.

6 0
3 years ago
A train is moving in a straight railway where it covered one third of the distance with
Alexxandr [17]

Answer:

<em>The average speed of the train is 45 km/h</em>

Explanation:

<u>Speed</u>

It's defined as the distance (d) per unit of time (t) traveled by an object. The formula is:

\displaystyle v=\frac{d}{t}

Let's call x the total distance covered by the train. It covered d1=1/3x with a speed of v1=25 km/h. The time taken is calculated solving for t:

\displaystyle t_1=\frac{d_1}{v_1}

\displaystyle t_1=\frac{1/3x}{25}

\displaystyle t_1=\frac{x}{75}

Now the rest of the distance:

d2 = x - 1/3x = 2/3x

Was covered at v2=75 km/h. Thus the time taken is:

\displaystyle t_2=\frac{d_2}{v_2}

\displaystyle t_2=\frac{2/3x}{75}

\displaystyle t_2=\frac{2x}{225}

The total time is:

\displaystyle t_t=\frac{x}{75}+\frac{2x}{225}

\displaystyle t_t=\frac{3x}{225}+\frac{2x}{225}

\displaystyle t_t=\frac{5x}{225}

Simplifying:

\displaystyle t_t=\frac{x}{45}

The average speed is the total distance divided by the total time:

\displaystyle \bar v=\frac{x}{\frac{x}{45}}

Simplifying:

\boxed{\displaystyle \bar v=45\ km/h}

The average speed of the train is 45 km/h

5 0
3 years ago
A diagram of a closed circuit with a power source on the left labeled 120 V. There are 3 resistors in parallel, separate paths,
Zina [86]

1) The equivalent resistance is 2.73\Omega

2) The voltage in the circuit is 120 V

3) The total current in the circuit is 44.0 A

Explanation:

1)

Resistors are said to be in parallel when they have the same potential difference at their terminals.

The formula to calculate the equivalent resistance for three resistors in parallel is:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where R_1, R_2, R_3 are the resistances of the three resistors.

In this problem, the resistance of each resistor is:

R_1 = 5.0 \Omega

R_2 = 10.0 \Omega

R_3 = 15.0 \Omega

Substituting,

\frac{1}{R_T}=\frac{1}{5}+\frac{1}{10}+\frac{1}{15}=\frac{11}{30}

So the equivalent resistance is

R_T = \frac{30}{11}=2.73 \Omega

2)

In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

Therefore, the voltage in each branch containing each resistor is the same, and it is equal to the voltage of the battery, which is

V=120 V

So, the voltage in the circuit is 120 V.

3)

The total current in the circuit can be found by using Ohm's law:

V=RI

where

V is the voltage

R is the equivalent resistance of the circuit

I is the current

In this circuit, we have:

V = 120 V

R=2.73\Omega

Re-arranging the equation for I, we find the current:

I=\frac{V}{R}=\frac{120}{2.73}=44.0 A

Learn more about current and potential difference:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

4 0
3 years ago
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