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Feliz [49]
3 years ago
11

Two planets orbit a far away star as shown. Is it possible that both planets experience the same gravitation force from the star

?
A) No, it is not possible.
B) Yes, it is possible if the closer planet has less mass.
C) Yes, it is possible if the closer planet as a smaller radius.
D) Yes, it is possible if the closer planet orbits the star in a shorter time.

Physics
1 answer:
Vesna [10]3 years ago
8 0

As we know that gravitational force on two planets will be given as

let

mass of star = M

mass of two planets are m1 and m2

their distance from star is r1 and r2

F = \frac{GMm_1}{r_1^2} = \frac{GMm_2}{r_2^2}

since the gravitational force of star is given on two planets to be same

so here we can say

\frac{m_1}{r_1^2} = \frac{m_2}{r_2^2}

now if the ratio of mass and distance is same then we can say that closer planet must have lesser mass to hold good for above equation

so correct answer will be

B) Yes, it is possible if the closer planet has less mass.

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T ref = reference temperature that ∝ is specified at for the conductor material

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1.E(r) = \frac{\alpha}{4\pi \epsilon_0}(2 - \frac{r}{R})

2.E(r) = \frac{1}{4\pi \epsilon_0}\frac{\alpha R}{r}

3.The results from part 1 and 2 agree when r = R.

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We will investigate this question in two parts. First r < R, then r > R. We will show that at r = R, the solutions to both parts are equal to each other.

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\int {\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

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Q_{enc} = \int\limits^r_0 {\rho(r)h} \, dr = \alpha h \int\limits^r_0 {(1-r/R)} \, dr = \alpha h (r - \frac{r^2}{2R})\left \{ {{r=r} \atop {r=0}} \right. = \alpha h (\frac{2Rr - r^2}{2R})\\E2\pi rh = \alpha h \frac{2Rr - r^2}{2R\epsilon_0}\\E(r) = \alpha \frac{2R - r}{4\pi \epsilon_0 R}\\E(r) = \frac{\alpha}{4\pi \epsilon_0}(2 - \frac{r}{R})

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3. At the boundary where r = R:

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