Answer:
The centripetal acceleration will be "21.785 m/s²".
Explanation:
The given values are:
Time,
t = 0.85 seconds
Length of rope,
r = 0.40 m
Mass of ball,
m = 0.80 kg
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
The centripetal acceleration will be:
⇒ 
⇒ 
⇒ 
⇒ 
When an object falls or is dropped from rest it's initial velocity is zero.
Using the equations for a motion in straight line. I can find the time it takes to reach 3.0 m down (half way).
x = vt - 4.9t²
-3 = 0 - 4.9t²
-3/-4.9 = t²
0.6122 = t²
0.7825 sec = t
v = v - gt
v = 0 - 9.8(0.7825)
v = -7.67 m/s
the negative denotes downward direction.
You could also solve the problem using potential and kinetic energy.
Since it starts with maximum PE and gets converted to KE when it hits the ground. mgh = mv²/2
mass cancels, use 3 meters for the halfway distance
-9.8(-3) = v²/2
29.4 * 2 = v²
√(58.8) = 7.67 m/s downwards
The change in electric potential energy is given by:
ΔU = ΔVq
ΔU = change in PE, ΔV = potential difference, q = charge
Given values:
ΔV = 50V - 20V = 30V, q = 0.14C
Plug in and solve for ΔU:
ΔU = 30(0.14)
ΔU = 4.2J
An electron cloud represents all the orbitals in an atom.
You asked the question twice I answered it on the last one