Answer:
The correct answer is 23,4375 grams of C.
Explanation:
First, we will identify the limiting reagent, which is the one consumed first. Since each gram of B consumes two grams of A, the product to be consumed first is A.
We calculate the amount of A and B that is consumed in the first 10 minutes is 5 grams of B and 10 grams of A.
Now we calculate the constant that relates the speed of reaction to the amount of reagent in each component.
20 grams of B and 40 grams of A will react completely given the limiting reagent A. We calculate the constant that relates the reaction speed (grams of product/time) with the instantaneous amounts of unconverted A and B. We calculate the constant that relates the reaction speed (grams of product/time) with the instantaneous amounts of unconverted A and B. We calculate the constant that relates the reaction speed (grams of product/time) with the instantaneous amounts of unconverted A and B.
So:
15g/10min = k*(20g*40g)
k=1.5 g/min / 800 g^2
k=1,875 *10^-3 g^3 /min
Now, we calculate the amount of reagent that forms when 20 minutes pass:
x / 10 min = 1,875 *10^-3 g^3/min * (15g * 30g)
x= 8,4375 grams
So we can say that after 20 minutes, 23.4375 grams of C will form.
Have a nice day!
B: Liquid take the shape of their container.
6= atom
1=mass
2=matter
3=weight
4=compound
5=molecule
Hoops this help
Taking into account the definition of dilution, moles of solute (option C) is the only thing about the solution that does NOT change.
<h3>Dilution</h3>
When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
<h3>Summary</h3>
In summary, moles of solute (option C) is the only thing about the solution that does NOT change.
Learn more about dilution:
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Answer:
<h3>the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
Explanation:
Amount of HBr dissociated
2HBr(g) ⇆ H2(g) + Br2(g)
Initial Changes 2.15 0 0 (mol)
- 0.789 + 0.395 + 0.395 (mol)
At equilibrium 1.361 0.395 0.395 (mole)
Concentration 1.361 / 1 0.395 / 1 0.395 / 1
at equilibrium (mole/L)
![K_c=\frac{[H_2][Br_2]}{[HBr]^2} \\\\=\frac{(0.395)(0.395)}{(1.361)^2} \\\\=\frac{0.156025}{1.852321} \\\\=0.084](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BBr_2%5D%7D%7B%5BHBr%5D%5E2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B%280.395%29%280.395%29%7D%7B%281.361%29%5E2%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B0.156025%7D%7B1.852321%7D%20%5C%5C%5C%5C%3D0.084)
<h3>Therefore, the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
