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Basile [38]
3 years ago
15

1. 1-propanol can form __________ with _______, but butane cannot.2. 1-propanol is more soluble than ethyl methyl ether because

it can form more _______ with _______.3. Ethanol is more soluble in water than 1-hexanol because it has ______.
Chemistry
1 answer:
12345 [234]3 years ago
8 0

Answe:

1. 1-propanol can form Hydrogen Bonds with other alcohol molecules but butane cannot.

2. 1-propanol is more soluble than ethyl methyl ether because it can form more hydrogen bonds with water.

3. Ethanol is more soluble in water than 1-hexanol because it has ethanol has shorter carbon chain whereas 1-hexanol has longer carbon chains.

Explanation:

Propanol can react with other alcohol molecules through hydrogen bonding to form ethers because alcohols do not dehydrate to form alkenes. They do this through that Williamson Ether Synthesis. In other words, alcohols can serve as an acid and a base in reactions. Butane do not follow this process.

Propanol can form hydrogen bonds with water making it more soluble than ethyl methyl ether. Propanol can donate and accept electrons which makes them interact with water better than ethyl methyl ether which can only receive proton from water.

Ethanol is mode soluble than hexanol beacuse it's non polar chain is shorter unlike in hexanol with a longer chain. Both alcohols has hydoxyl group which makes them soluble in water but their solubility is greatly affected by the remaining non polar side of the alcohol. Long non polar chain reduces solubility and vice versa.

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The simple trick which one can consider in such problem where it is asked for positron emission is :
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<span>a.  </span>P^{30}_{15}  ----\ \textgreater \   Si^{30}_{14} + e^{0}_{1}^+
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Here the atomic number decreases by one.

Similarly, options b and d are eliminated.

Option c is also not the answer.
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3 years ago
What is the density of aluminum in grams per cubic centimeter?
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Answer:

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Explanation:

Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:

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Units: g/cm^3 or kg/m^3

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3 years ago
Write a chemical equation of Dr. Jeff’s demonstration using a battery to light steel wool on fire. The battery is used to allow
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Answer:

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Explanation:

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Iron reacts with oxygen under these conditions as follows;

2Fe(s) + 3O2(g) --------> 2FeO3(s)

This is the chemical reaction that occurs when the steel wool is set on fire.

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Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

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Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

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The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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