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Basile [38]
3 years ago
15

1. 1-propanol can form __________ with _______, but butane cannot.2. 1-propanol is more soluble than ethyl methyl ether because

it can form more _______ with _______.3. Ethanol is more soluble in water than 1-hexanol because it has ______.
Chemistry
1 answer:
12345 [234]3 years ago
8 0

Answe:

1. 1-propanol can form Hydrogen Bonds with other alcohol molecules but butane cannot.

2. 1-propanol is more soluble than ethyl methyl ether because it can form more hydrogen bonds with water.

3. Ethanol is more soluble in water than 1-hexanol because it has ethanol has shorter carbon chain whereas 1-hexanol has longer carbon chains.

Explanation:

Propanol can react with other alcohol molecules through hydrogen bonding to form ethers because alcohols do not dehydrate to form alkenes. They do this through that Williamson Ether Synthesis. In other words, alcohols can serve as an acid and a base in reactions. Butane do not follow this process.

Propanol can form hydrogen bonds with water making it more soluble than ethyl methyl ether. Propanol can donate and accept electrons which makes them interact with water better than ethyl methyl ether which can only receive proton from water.

Ethanol is mode soluble than hexanol beacuse it's non polar chain is shorter unlike in hexanol with a longer chain. Both alcohols has hydoxyl group which makes them soluble in water but their solubility is greatly affected by the remaining non polar side of the alcohol. Long non polar chain reduces solubility and vice versa.

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Answer:

A = -213.09°C

B = 15014.85 °C

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Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

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Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

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