Use Newton's second law. The net force on the hero is
∑ <em>F</em> = <em>T</em> - <em>m g</em> = <em>m</em> (2.00 m/s²)
where
• <em>T</em> = tension in the rope
• <em>m</em> = 75.0 kg = mass of the hero
• <em>g</em> = 9.80 m/s² = acceleration due to gravity
Solve for <em>T</em> :
<em>T</em> = (75.0 kg)<em> </em>(<em>g</em> + 2.00 m/s²) = 885 N
Answer: a = 1, b = 9, c = 6, d = 4
Explanation:
With no velocity, total mechanical energy is all gravity potential energy
PE = mgh = 80.0(9.81)(25) = 19,620 J = 1.96e4 J
Answer:
h = 181.73 m
Explanation:
given,
distance between the neighbors = 42 m
speed of the rock rolling = 6.9 m/s
vertical velocity of ball = 0 m/s
height of the cliff = ?
time taken by the ball to travel 42 m
d = s x t
s is the horizontal speed of the ball equal to 6.9 m/s
t = 6.09 s
same time will be taken by the ball to travel vertical distance
Using equation of motion
h = 181.73 m
Answer:
The magnitude of the magnetic torque on the coil is 1.98 A.m²
Explanation:
Magnitude of magnetic torque in a flat circular coil is given as;
τ = NIASinθ
where;
N is the number of turns of the coil
I is the current in the coil
A is the area of the coil
θ is the angle of inclination of the coil and magnetic field
Given'
Number of turns, N = 200
Current, I = 7.0 A
Angle of inclination, θ = 30°
Diameter, d = 6 cm = 0.06 m
A = πd²/4 = π(0.06)²/4 = 0.002828 m²
τ = NIASinθ
τ = 200 x 7 x 0.002828 x Sin30
τ = 1.98 A.m²
Therefore, the magnitude of the magnetic torque on the coil is 1.98 A.m²
