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umka21 [38]
3 years ago
12

Part A

Physics
1 answer:
forsale [732]3 years ago
8 0

Answer:

Explanation:

A )

L_{max} = \sqrt{l(l+1)}ℏ

where l is orbital quantum number

l = n-1 where n is principal quantum no

Given n = 7

l = 7 - 1 = 6

L_{max} = \sqrt{6(6+1)}ℏ

= 6.48ℏ

B)

Here

n = 26

l = 26 - 1

= 25

L_{max} = \sqrt{25(25+1)}ℏ

= 25.49ℏ

= 25.5ℏ

C )

n = 191

l = 191 - 1

190

L_{max} = \sqrt{190(190+1)}

= 190.499ℏ

= 191ℏ

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Why does the pattern of colors repeat in a thin soap film? Please use 2 content related sentences
alexgriva [62]

Answer:

1) Some light waves bounce off the inner part of the film.

2) In doing so they travel a bit than the waves bouncing off the outer waves.

so we see colors repeat in pattern in a thin soap film

Explanation:

A colorful interference pattern is observed when light is reflected from the top and bottom boundaries of a thin oil film. The different bands form as the film's thickness diminishes from a central runoff-point.

When white light shines on a bubble, strange things happen. When light waves hit a bubble, some of them bounce straight back off the outer part of the soap film. Others carry on through but then bounce off the inner part of the film. So one set of light rays shine into a soap bubble, but two sets of rays come back out again. When they emerge, the waves that bounce off the inner film have traveled a tiny bit further than the waves that bounced off the outer film. So we have two sets of light waves that are now slightly out of step. Like two sets of ripples on a pond, these waves start merging. Just like on a pond, some add together and some cancel out. The overall effect is that some of the colors in the original white light disappear altogether, leaving other colors behind. These are the colors you see in soap bubbles.

5 0
4 years ago
A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir
Nataly [62]

Answer:v_1=28.4 cm/s

Explanation:

Given

mass of marble m_1=27 gm

velocity of marble u_1=56.8 cm/s \approx 0.568 m/s

mass of second marble m_2=13.5 gm

Velocity of second marble u_2=14.2 cm/s \approx 0.142 m/s

After collision 13.5 gm marble moves to the right  at i.e. v_2=71 cm/s

Conserving momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71

1533.6+191.7=27\cdot v_1+958.5

27\cdot v_1=766.8

v_1=\frac{766.8}{27}=28.4 cm/s

7 0
3 years ago
Interactive Solution 22.43 provides one model for solving this problem. The maximum strength of the earth's magnetic field is ab
laila [671]

Answer:

427097

Explanation:

V = Voltage = 170 V

B = Magnetic field = 6.9\times 10^{-5}\ T

f = Frequency = 54.1 Hz

A = Area = 0.024\ m^2

Number of turns is given by

N=\dfrac{V\sqrt{2}}{BA2\pi f}\\\Rightarrow N=\dfrac{170\sqrt{2}}{6.9\times 10^{-5}\times 0.024\times 2\pi\times 54.1}\\\Rightarrow N=427096.933536\approx 427097\ turns

Number of turns is 427097

5 0
4 years ago
Which is a example of speed? A)Cindy biked westward at 30km/h B)A Rock is the the left of a flowerpot C) A dog runs an average o
finlep [7]
I think the answer is A) Cindy biked westward at 30km/h. I'm sorry if I'm wrong. If that's not correct then it's definitely C) A dog runs an average of 8mp/h. I hope this helps. :) 
4 0
4 years ago
Read 2 more answers
A cruise ship with a mass of 1.00 \times 10^7 \,\mathrm{kg}1.00×10 7 kg strikes a pier at a speed of 0.750\,\mathrm{m/s}0.750m/s
mote1985 [20]

Answer:

F_i=4.6875x10^5 N

Explanation:

Given:

m=1x10^7 kg

u=0.750 m/s

s=6m

First determinate the time using equation of Newton's law

d=\frac{uf+ui}{2}*t

uf=0 solve to t'

t=\frac{2*d}{u_i}=\frac{2*6m}{0.75m/s}

t=16s

The impulse concept tells about the force in terms of velocity so:

F=m*a

a=\frac{u'}{t'}

F_i=m*\frac{u}{t}=1x10^7kg\frac{0.750m/s}{16s}

F_i=4.6875x10^5 N

5 0
4 years ago
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