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3 years ago

Part A

Physics

1 answer:

forsale [732]3 years ago

8 0

Answer:

Explanation:

A )

$L_{max} = \sqrt{l(l+1)}$ ℏ

where l is orbital quantum number

l = n-1 where n is principal quantum no

Given n = 7

l = 7 - 1 = 6

$L_{max} = \sqrt{6(6+1)}$ ℏ

= 6.48ℏ

Here

n = 26

l = 26 - 1

= 25

$L_{max} = \sqrt{25(25+1)}$ ℏ

= 25.49ℏ

= 25.5ℏ

C )

n = 191

l = 191 - 1

190

$L_{max} = \sqrt{190(190+1)}$

= 190.499ℏ

= 191ℏ

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