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umka21 [38]
3 years ago
12

Part A

Physics
1 answer:
forsale [732]3 years ago
8 0

Answer:

Explanation:

A )

L_{max} = \sqrt{l(l+1)}ℏ

where l is orbital quantum number

l = n-1 where n is principal quantum no

Given n = 7

l = 7 - 1 = 6

L_{max} = \sqrt{6(6+1)}ℏ

= 6.48ℏ

B)

Here

n = 26

l = 26 - 1

= 25

L_{max} = \sqrt{25(25+1)}ℏ

= 25.49ℏ

= 25.5ℏ

C )

n = 191

l = 191 - 1

190

L_{max} = \sqrt{190(190+1)}

= 190.499ℏ

= 191ℏ

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Given Information:

Magnetic field = B = 1×10⁻³ T

Frequency = f = 72.5 Hz

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Required Information:

Maximum Emf = ?

Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

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Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

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Area is given by

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