Where the solubility product Ksp is applied where salts don't fully dissolve in a solvent.
and when the reaction equation is:
AB2(s) ↔ A2+(Aq) + 2 B-(aq)
so we have the Ksp expression = [A2+][B-]^2
when we assume [A2+] = X = 0.01 M
and [B-] = 2X = 2*0.01 M = 0.02 M
So by substitution:
Ksp = 0.01 * (0.02)^2
= 4 x 10^-6
Answer:
The correct answer is A. Barium Chloride
Explanation:
Answer:
Explanation:
1. Moles of CCl₄
2. Molar mass of CCl₄
MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol
3. Mass of CCl₄
4. Volume of CCl₄
Because there are so many different values of numbers, it would be impractical to use 1Ω, 2Ω, 3Ω... etc... Using colored bands helps make reading it a little easier to the trained eye. There are hundreds of thousands, if not tens of millions of different resistors would need to exist to cover every value. So you just use something called "preferred values" with their resistance values posted on them instead.
