All categories

3 years ago

A car, starting from the origin, travels

Physics

2 answers:

sweet [91]3 years ago

8 0

Answer:

The net displacement of the car is 3 km West

Explanation:

Please see the attached drawing to understand the car's trajectory: First in the East direction for 4 km (indicated by the green arrow that starts at the origin (zero), and stops at position 4 on the right (East).

Then from that position, it moves back towards the West going over its initial path, it goes through the origin and continues for 3 more km completing a moving to the West a total of 7 km. This is indicated in the drawing with an orange trace that end in position 3 to the left (West) of zero.

So, its NET displacement considered from the point of departure (origin at zero) to the final point where the trip ended, is 3 km to the west.

AleksandrR [38]3 years ago

8 0

The net displacement of the car from the initial point will be 3 kilometer west.

<u>Explanation:</u>

Displacement is the shortest distance between two points, whereas the distance is the total distance between two points.

Displacement is a vector quantity and distance is scalar quantity. Let the car starts from point A and reaches point B in the East direction, i.e., 4 km.

Now from point B it starts moving west and reaches point C beyond point A, i.e., 7 km.

A---------------------.>B 4KM

C <--------------------------------------------B 7KM

finally the resultant distance is 3 km west

You might be interested in

If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move

alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: $m=22kg$

coefficient of friction: $\mu =0.27$

and we also know the acceleration of gravity is $g=9.81m/s^2$

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

Normal force $N$ (acting up from the object)

weight: $w=mg$ (acting down from)

so the sum of forces in the vertical axis "y" are:

$F_{y}=N-w\\F_{y}=N-mg$

from Newton's second Law we know that $F=ma$ , so:

$ma_{y}=N-mg$

and since the object is not accelerating in the vertical direction (the movement is only horizontal) $a_{y}=0$ , and:

$0=N-mg\\N=mg$

-----------

now let's analyze the horizontal forces

frictional force: $f= \mu N$ and since $N=mg$ --> $f=\mu mg$

force to move the object: $F$

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

$F=ma_{x}=F-f\\ma_{x}=F-\mu mg$

and we are told that the crate moves at a steady speed, thus there is no acceleration: $a_{x}=0$

and we get:

$0=F-\mu mg\\F=\mu mg$

substituting known values:

$F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N$

3 0

3 years ago

3% of earth's water is?

Luda [366]

Is earth’s freshwater

Only about 3 percent of Earth’s water is fresh water.

8 0

3 years ago

A unit of area, often used in measuring land areas, is the "hectare", defined as 104 m2. An open-pit coal mine consumes 72 hecta

lara31 [8.8K]

Answer:

0.018 km³

Explanation:

Area of land

$A=72\times 10^4\ m^2$

D = Depth of land = 25 m

Volume is given by

$V=AD\\\Rightarrow V=72\times 10^4\times 25\\\Rightarrow V=18000000\ m^3$

Converting to cubic kilometers

$1\ m=\dfrac{1}{1000}\ km$

$1\ m^3=\dfrac{1}{1000^3}\ km^3$

$18000000\ m^3=18000000\times \dfrac{1}{1000^3}=0.018\ km^3$

The volume of Earth removed is 0.018 km³

5 0

4 years ago

Two 2.5 kg bowling balls are 0.50 m apart. What is the force of gravity of the first bowling ball due to the

Makovka662 [10]

Answer:The answer is A

Explanation:

To determine the force, we use the equation

Fg= G m1 m2/r2

, where Fg is the force of gravity, G is the gravitational constant,

is the mass of the first body,

is the mass of the second body, and r is the radius. Hence, we have

Fg=6.67×10−11 N×m2/kg2×2.5 kg×2.5 kg/(0.50 m)2=1.7×10−9N

. Since this is a gravitational problem, the force on one body has the same force as the other body, but the directions are opposite.

5 0

3 years ago

Why is it important to have a balanced centrifuge?

ratelena [41]

It is important to properly balance a centrifuge because an unbalanced machine can damage the rotor, cause catastrophic damage to the machine itself, or even injure or kill lab personnel working in the room. Balancing a centrifuge involves spreading the weight of the samples across the entire rotor.

8 0

4 years ago