A polar bear starts at the North Pole. It travels 1.0 km south, then 1.0 km east, then 1.0 km north, then 1.0 km west to return
1 answer:
Answer:
The average speed of the bear is 5.3 km/h.
Explanation:
Hi there!
The average <u>speed</u> is calculated as the distance traveled divided by the time in which that distance was covered. The bear traveled 4 km (1 km south, 1 km east, 1 km north and 1 km west) in 45 min. It does not matter the direction at which the bear traveled, only how much distance the bear moved. So the average speed (a.s) will be:
a.s = d/t
Where:
d = traveled distance.
t = time in which that distance was covered.
The average speed of the bear is 5.3 km/h.
Notice that if the question would have asked to find the average <u>velocity,</u> the answer would have been zero because the total displacement of the bear was zero (it returned to the initial point). The average velocity is calculated as the displacement over time.
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Answer:
The transverse component of acceleration is 26.32 where as radial the component of acceleration is 8.77
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s
So the transverse component of acceleration are given as
Here
So
The transverse component of acceleration is 26.32
The radial component is given as
Here
So
The radial component of acceleration is 8.77
Answer:
0m/s²
Explanation:
Given parameters:
Initial velocity of the boat = 8m/s
Final velocity = 8m/s
Time taken = 4s
Unknown:
Acceleration of the boat = ?
Solution:
Acceleration is the rate of change of velocity with time.
It is mathematically expressed as;
A =
A is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
Insert the parameters and solve;
A = = 0m/s²