The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)
Molar mass
Ca₃(PO₄)₂ = 310 g/mol
1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?
m = 2.3x10⁻⁴ * 310 / 1
m = 0.0713 g
hope this helps!
Answer:
1. 15.71 g CO2
2. 38.19 % of efficiency
Explanation:
According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:
For CO:
C = 12.01 g/mol
O = 16 g/mol
CO = 28.01 g/mol
(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO
For CO2:
C = 12.01 g/mol
O = 16 x 2 = 32 g/mol
CO2 = 44.01 g/mol
We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:
(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2
We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:
(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2
Now for the efficiency question:
From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,
(6g / 15.71g) x 100 = 38.19 % of efficiency
Answer : The concentration of silver ion is, 
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
The expression of 
will be,
![K_{eq}=[Ag^+]^2[S^{2-}]](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5BAg%5E%2B%5D%5E2%5BS%5E%7B2-%7D%5D)
![2.4\times 10^{-4}=(2.5\times 110^{-1})^2[S^{2-}]](https://tex.z-dn.net/?f=2.4%5Ctimes%2010%5E%7B-4%7D%3D%282.5%5Ctimes%20110%5E%7B-1%7D%29%5E2%5BS%5E%7B2-%7D%5D)
![[S^{2-}]=3.8\times 10^{-3}M](https://tex.z-dn.net/?f=%5BS%5E%7B2-%7D%5D%3D3.8%5Ctimes%2010%5E%7B-3%7DM)
Therefore, the concentration of silver ion is,
Answer:
please brainlist answer
Explanation:
The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.
