What's the relationship between work done and force applied

1 answer:

3 0

When a force acts on a body along some path, the work done is W=F*s, where W is the work done, F is the force that is doing the work on the body and s is the path. The force doing the work has to be in the same direction, or parallel, as the path. This is called positive work. If the force and the path are anti-parallel, the work is negative. So the relationship between work and force is W=F*s.

You might be interested in

The diagram below shows the reactants and products of a chemical reaction. What property of reactions does this diagram illustra

Paladinen [302]

Based on the chemical reaction, Carbon reacts with Oxygen would yield Carbon Dioxide, we can imply that the "<span>Atoms are always conserved during chemical reactions." It is one of the fundamental concepts in chemistry wherein the mass is always conserved in a reaction since it can't be created nor destroyed.</span>

5 0

3 years ago

The distance between two parallel wires carrying currents of 10 A and 20 A is 10 cm. Determine the magnitude and direction of th

Marianna [84]

Explanation:

It is given that,

Current in wire 1, I₁ = 10 A

Current in wire 2, I₂ = 20 A

Distance between wires, d = 10 cm = 0.1 m

Force per unit length is given by :

$\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}$

$\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 10\times 20}{2\pi \times 0.1}$

$\dfrac{F}{l}=0.0004\ N/m$

$\dfrac{F}{l}=4\times 10^{-4}\ N/m$

So, the magnetic force acting per unit length of the wires $4\times 10^{-4}\ N/m$ . Since, the current is in same direction. So, the force is attractive in nature.

6 0

3 years ago

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length t

gladu [14]

The question is incomplete. The complete question is :

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length to compute the average force of friction (for this calculation, you may neglect uncertainties).

Mass of the ball : 16.3 g

Predicted range : 0.3503 m

Actual range : 1.09 m

Solution :

Given that :

The predicted range is 0.3503 m

Time of the fall is :

$t=\sqrt{\frac{2H}{g}}$