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bixtya [17]
3 years ago
14

A 497−g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assumi

ng no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system (c of copper = 0.387 J/g·°C)?

Physics
1 answer:
algol [13]3 years ago
6 0

Answer:

36.6 degree centigre

Explanation:

Check the attached file below

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The pressure and volume of a fixed mass of gas _ are related. if one decreases, the other ___ ___ this relationship is known as
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<span>The pressure and volume of a fixed mass of gas are inversely related. If one decreases, the other increases. This relationship is known as Boyle's law. The volume of a fixed mass of a gas is directly proportional to its kelvin temperature. This relationship is known as Charles's law. Gay-Lussac's law states that the pressure of a gas is directly proportional to the kelvin temperature if the volume remains constant. These three separate gas laws can be written as a single expression called the combined gas law. It can be used in situations in which only the amount of gas is constant. </span>

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3 years ago
6. Dan wants to create acceleration. He
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d. Maintain constant velocity

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Acceleration brainly.com/question/3820012

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A 50 kg pitcher throws a baseball with a mass of 0.15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is
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The velocity of the pitcher is <u>0.105 m/s</u> in a direction opposite to the velocity of the ball.

When no external force acts on a system, the total momentum of the system is conserved. The total initial momentum of the system is equal to the total final momentum of the system.

The pitcher and the ball are initially at rest, therefore, the total initial momentum of the system is zero.

Since no external forces act on the system comprising of pitcher and the ball, the total final momentum of the system is also equal to zero.

If the mass of the pitcher is mp and its speed is vp, the mass of the ball is mb and the ball's speed is vb, then the final momentum of the system of pitcher and the ball is given by,

p=m_pv_p+m_bv_b=0

Therefore,

v_p=-\frac{m_b}{m_p} v_p

Substituet 0.15 kg for mb, 50 kg for mp and 35 m/s for vb.

v_p=-\frac{m_b}{m_p} v_p=-\frac{0.15 kg}{50 kg} (35m/s)=-0.105 m/s

The pitcher has a velocity <u> 0.105 m/s</u> opposite to the direction of the velocity of the ball.

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