Ask question

Ask question

All categories

3 years ago

14

A 497−g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assumi

ng no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system (c of copper = 0.387 J/g·°C)?

1 answer:

algol [13]3 years ago

6 0

Answer:

36.6 degree centigre

Explanation:

Check the attached file below

You might be interested in

A ball is thrown with a velocity of 10 m/s at a 25º from the horizontal. How far does the ball travel?

Stels [109]

Answer:

use a=v-u/t formula it will be correct

5 0

3 years ago

PLEASE HELP ASAP!!! 49 POINTS AND BRAINLIEST FOR BEST AND FASTEST ANSWER!!! (DO NOT ANSWER IF YOU DON'T KNOW, OR I WILL REPORT Y

Colt1911 [192]

Neap tide = tide where there is the least difference between high and low water levels

Spring tide = tide where there is the greatest difference between high and low water levels

Equator = an imaginary line drawn around earth dividing it into northern and southern hemispheres

Seasons = the divisions of the year marked by specific weather patterns and daylight hours.

Hope this helps!

5 0

3 years ago

Read 2 more answers

A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What

Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

We know that,

$m_{p}c^2=m_{np}c^2$

So, $E_{photon}=2mc^2+K.E_{p}+K.E_{np}$

$K.E_{np}=E_{photon}-(2mc^2+K.E_{p})$

Put the value into the formula

$K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}$

$K.E_{np}=147.4\ MeV$

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0

3 years ago

A particle that has a charge of 7.4 μC moves with a velocity of magnitude 3 × 105 m/s along the +x axis. It experiences no magne

sweet [91]

Answer:

Explanation:

F = qvB

Where F equal to the magnetic force on the particle.

q = charge on the particle

v = velocity of the particle

B =Magnetic field

F = 0.520N

q = 7.4 μC = 7.4×10-⁶C

v = 3×10⁵m/s

B= ?

B = F/qv

B = 0.520/(7.4×10-⁶ ×3×10⁵)

B = 0.234T.

6 0

3 years ago

If people are going to cut down a tree anyway, what difference does

Dafna11 [192]

Fruit trees are important because they can make more trees from the seeds of their fruit. regular trees just drop leaves and pollen

3 0

3 years ago

Read 2 more answers