All categories

3 years ago

true or false, Discovering which of two materials can scratch the other is a way to compare the hardness of the materials

Chemistry

2 answers:

Shkiper50 [21]3 years ago

7 0

True, the hardness of all materials in relative <span />

Anton [14]3 years ago

7 0

This answer is true :)

You might be interested in

AP CHEMISTRY -If any of these questions in the image (NET IONIC BALANCED EQUATIONS w/ states of matter) can be answered, especia

OLga [1]

3) CH₃-COOH + NH₃ → CH₃-COO⁻NH₄⁺

4) 2 FeCl₃ + 3 Ag₂SO₃ → Fe₂(SO₃)₃ + 6 AgCl

5) 2 Al + 3 NiCl₂ → 2 AlCl₃ + 3 Ni

6) 4 LiCl + Pb(NO₂)₄ → 4 LiNO₂ + PbCl₄

7) 3 H₂SO₄ + 2 Al(OH)₃ → Al₂(SO₄)₃ + 6 H₂O

8) Cd(NO₃)₂ + Na₂S → CdS + 2 NaNO₃

9) Cr₂(SO₄)₃ + 3 (NH₄)₂CO₃ → Cr₂(CO₃)₃ + 3 (NH₄)₂SO₄

5 0

4 years ago

Please help I’m being timed In many thermodynamically favored reactions, the total bond energy of the products is lower than the

zzz [600]

The answer is A, exothermic

5 0

3 years ago

Rank the members of each set of compounds according to the ionic character of their bonds. Most ionic bonds?a) PCl3 PBr3 PF3 Mos

SCORPION-xisa [38]

Explanation:

More is the electronegativity difference between the combining atoms more polar is the compound. Hence, more ionic it will be in nature.

(a) Electronegativity value of P = 2.19

Electronegativity value of Cl = 3.16

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a P-Cl bond = 3.16 - 2.19 = 0.97

Electronegativity difference of a P-Br bond = 2.96 - 2.19 = 0.77

Electronegativity difference of a P-F bond = 3.98 - 2.19 = 1.79

Since, a P-F bond has the highest electronegativity difference. Therefore, $PF_{3}$ is the most ionic compound and $PBr_{3}$ is the least ionic compound.

(b) Electronegativity value of B = 2.04

Electronegativity value of N = 3.04

Electronegativity value of C = 2.55

Electronegativity value of F = 3.98

Electronegativity difference of a B-F bond = 3.98 - 2.04 = 1.94

Electronegativity difference of a N-F bond = 3.04 - 3.98 = 0.94

Electronegativity difference of a C-F bond = 3.98 - 2.55 = 1.43

Since, a B-F bond has the highest electronegativity difference. Therefore, $BF_{3}$ is the most ionic compound and $NF_{3}$ is the least ionic compound.

(c) Electronegativity value of Se = 2.55

Electronegativity value of Te = 2.1

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a Se-F bond = 3.98 - 2.55 = 1.43

Electronegativity difference of a Te-F bond = 3.98 - 2.1 = 1.88

Electronegativity difference of a Br-F bond = 3.98 - 2.19 = 1.02

Since, a Te-F bond has the highest electronegativity difference. Therefore, $TeF_{4}$ is the most ionic compound and $BrF_{3}$ is the least ionic compound.

6 0

3 years ago

Which temperature is required for the cell potential to be the standard cell potential?

In-s [12.5K]

25° C is the temperature required for the cell potential to be the standard cell potential

8 0

4 years ago

Read 2 more answers

state the behaviour of equilibrium , of ammonia is removed from the reaction mixture . Explain your answer

OLEGan [10]

Equilibrium

N₂(g) + 3H₂(g) ⇔ 2NH₃(g)

If the concentration of the reactants is added, the system will reduce the concentration of the reactants by shifting towards the products and vice versa if the concentration of the reactants is decreased the system will shift towards the reactants.

ammonia is removed from the reaction mixture ⇒ it means the ammonia is reduced then the equilibrium shifts to the right

5 0

3 years ago