Draw the structure of the aromatic compound para-aminochlorobenzene (para-chloroaniline). Draw the molecule on the canvas by cho
osing buttons from the Tools
1 answer:
Answer:
Explanation:
In the picture you have the answer.
Now, let's analize the structure, so you can know why the structure in the picture is the correct structure.
The aniline is the name that receives the benzene with a NH2 group as one of it's substituent. Now, This group is a really strong activating group and in the nomenclature priority, it has more order priority than any halide.
Now, it says that the chloro it's on the para position. The "para" position in a aromatic ring, in this case, the benzene, refers to the position of this substituent to the first substitued position. In this case, the NH2 it's on the position 1 or carbon 1, the para position, means that it's on position 4 of the ring. The ortho position is carbon 2, and meta position is carbon 3 of the benzene. So, according to this, the p-chloroaniline it's on picture attached.
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A gas made up of atoms escapes through a pinhole 0.225times as fast as gas. Write the chemical formula of the gas.
Answer:
Explanation:
To solve this problem, we must apply Graham's law of diffusion. This law states that "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular mass at constant temperature and pressure".
Mathematically;
r₁ is the rate of diffusion of gas 1
r₂ is the rate of diffusion of gas 2
m₁ is the molar mass of gas 1
m₂ is the molar mass of gas 2
let gas 2 be the given H₂;
molar mass of H₂ = 2 x 1 = 2gmol⁻¹
rate of diffusion is 0.225;
i .e r1/r2 = 0.225
0.225 = √2 / √ m₁
0.225 = 1.414 / √ m₁
√ m₁ = 6.3
m₁ = 6.3² = 39.5g/mol
The gas is likely Argon since argon has similar molecular mass
Explanation:
An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.
Symbol of an alpha particle is . Whereas a neutron is represented by a symbol
, that is, it has zero protons and only 1 neutron.
Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.