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3 years ago

15

What is silica gel commonly used for? A. Absorbing moisture to protect goods from damage. B. As insulation in buildings. C. As a

lacquer on wood to make it water-resistant. D. A soft, flexible padding, such as on pen grips or mouse pads.

1 answer:

omeli [17]3 years ago

5 0

Answer:

A

Explanation:

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Substance which speed up the rusting process

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salt solution speeds up rusting processing

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What is bank?Effect of drug abuse.<br>

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- Long term effects

Chronic drug use can alter a person’s brain structure and function, resulting in long-term psychological effects, such as: depression, anxiety, panic disorders, increased aggression, paranoia, hallucinations.

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3 years ago

A solution is prepared by adding 91.3 g of sodium bromide [NaBr], to 115. g of water. Determine whether the solution is saturate

MrMuchimi

<u>Answer:</u> The given solution is unsaturated solution

<u>Explanation:</u>

We are given:

Solubility of NaBr = 9.19 m

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

A precipitate is defined as the insoluble salt which is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

There are three conditions:

When $m_{\text{(calculated)}}$ ; the solution is unsaturated
When $m_{\text{(calculated)}}=m_{\text{(given)}}$ ; the solution is saturated
When $m_{\text{(calculated)}}>m_{\text{(given)}}$ ; precipitate will form

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (sodium bromide) = 91.3 g

$M_{solute}$ = Molar mass of solute (sodium bromide) = 103 g/mol

$W_{solvent}$ = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

$\text{Calculated molality of NaBr}=\frac{91.3\times 1000}{103\times 115}\\\\\text{Calculated molality of NaBr}=7.71m$

As, the calculated solubility is less than the given solubility. So, the solution will be unsaturated.

Hence, the given solution is unsaturated solution

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